Lactococcus lactis is used in the production of buttermilk and cheese. Lactococcus lactis is what is known as a gram positive bacteria.
Yes is negative
From what I've found... Lactococcus lactis won't grow on a 6.5% plate while enterococcus faecalis will. Hope that helps!
-VE
in the broth they will be packed close together and more spread out in the slant
No it doesn't. Entercocci and members of the streptococcus group can.
Maysoon Salama has written: 'The isolation of Lactococcus lactis subsp. cremoris from nature with probes for 16S ribosomal RNAs' -- subject(s): Nucleic acid hybridization, Nucleic acid probes, RNA, Nucleotide sequence, Lactococcus lactis
There may be a variety of molds that grow on milk. The usual ones are lactic acid bacteria, which includes lactococcus lactis and lactobacillus bulgaricus.
There may be a variety of molds that grow on milk. The usual ones are lactic acid bacteria, which includes lactococcus lactis and lactobacillus bulgaricus.
To diagnose Enterococcus faecalis: (Facultative anaerobic) First, do the Gram stain: Gram positive cocci in chains catalase test: negative PYR disc: positive
The future tense of "survive" is "will survive" or "shall survive."
C(7,2)*(.9)^5*(.1)^2, or about .124 = 12.4% For the desired outcome, considering the seven patients, you need: (Survive,Survive,Survive,Survive,Survive,Die,Die) (Survive,Survive,Survive,Survive,Die,Survive,Die) (Survive,Survive,Survive,Die,Survive,Survive,Die) . . . (Die,Die,Survive,Survive,Survive,Survive,Survive) There are C(7,2) [the number of combinations of 7 things taken 2 at a time] = 21 possible desired outcomes. The probability of each of these outcomes is (.9)*(.9)*(.9)*(.9)*(.9)*(.1)*(.1). Multiplying 21 by (.9)*(.9)*(.9)*(.9)*(.9)*(.1)*(.1) yields the answer.