Inside of the thylakoid
When a ribsome reaches a stop codon, the translation process stops and a protein is released.
Hydrogen atom = 1 proton 1 electron Hydrogen's 1 electron occupies the lowest energy level, 1s orbital. The atom is therefore in its "ground state". When a photon of correct frequency "collides" with a electron in hydrogen's 1s orbital the energy contained in the photon is transferred to the electron. The electron then gets added energy, so it is at a higher energy state. When it reaches this higher energy state the electron jumps to the next energy level and there it starts its new orbit. Hydrogen atom is now "excited" For any other atoms it is the same thing because all atoms can undergo excitation. The only difference between hydrogen's 1 electron and other atom's many electrons is WHICH ELECTRON will be "excited"
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Hormones are released by the endocrine system.
the vast majority of the volume of an atom is filled with absolutely nothing there is a central heavy nucleus and "whizzing" round it are a number of much lighter much smaller electrons. from the outermost reaches of the electrons orbits to the centre of the nucleus there is an awful lot of "nothing" an analogy is to consider the earth we are a heavy central body - compare us to the nucleus of an atom whizzing round us are various satellites - the moon and many small artificial ones we have put up - compare them to the electrons in between and making up by far the bulk of the volume occupied by the "earth and its satellites" is a lot of nothing - just like in an atom
Inside of the thylakoid
The temperature in cells is not high enough. Each of the redox reactions in the electron transport chain are catalyzed by an enzyme. NADH dehydrogenase transfers electrons from NADH to ubiquinone, and cytochrome c oxidase transfers electrons from cytochrome c to oxygen. So there is no enzyme to pass the electrons directly from NADH to oxygen.
When a ribsome reaches a stop codon, the translation process stops and a protein is released.
Anywhere there is a wifi signal you have the password for. 3G models can get internet anywhere their carrier's cell signal reaches.
Energy is either absorbed or released. If the electron goes from a high energy orbital to a lower energy one, a photon is emitted. When a photon is absorbed, the electron goes from low energy to high.
Hydrogen atom = 1 proton 1 electron Hydrogen's 1 electron occupies the lowest energy level, 1s orbital. The atom is therefore in its "ground state". When a photon of correct frequency "collides" with a electron in hydrogen's 1s orbital the energy contained in the photon is transferred to the electron. The electron then gets added energy, so it is at a higher energy state. When it reaches this higher energy state the electron jumps to the next energy level and there it starts its new orbit. Hydrogen atom is now "excited" For any other atoms it is the same thing because all atoms can undergo excitation. The only difference between hydrogen's 1 electron and other atom's many electrons is WHICH ELECTRON will be "excited"
Ioniz. energy is the amount of energy it takes to remove one electron from an atom. Lithium has one too many electrons before it reaches the highly stable octet of the immediately previous noble gas- so it gives it up really easily. Carbon is farther away from the octet in this manner, so it will take more energy. Also, lithium is a metal and metals tend to lose electrons. Carbon, a nonmetal, tends to gain electrons.
By the time a star reaches the white dwarf stage, it's already about as compact as it's possible for ordinary matter to get... the size is maintained by electron degeneracy pressure, which is a fancy way of saying "the atoms are already touching, contracting any more would mean forcing the electrons into the nucleus."
When an object is released in a fluid is the drag force less than its weight before it reaches terminal velocity?
If you count up the number of valence electrons (including the extra electron from the -1 charge) you get: S + C + N + e- = 6 + 4 + 5 + 1 = 16 Divide this by 2 to get the electron pairs: 16/2 = 8 Now connect the atoms: S-C-N That used up two pairs... 8 - 2 = 6 left. Now place the remaining pairs of electrons around the outside atoms. this is hard to picture, but you put three around the sulfur before it reaches 8 electrons (the most it can have) and three around the nitrogen before it has 8 electrons. Finally, look at each atom to confirm it has 8 electrons around it. Sulfur has 8 (3 lone pairs and a bond), nitrogen has 8 (also 3 lone pairs and a bond), but carbon only has 4 (two bonds). To fix this, start forming double bonds using an electron pair each from the nitrogen and the sulfur. When you do this you get: S=C=N (with two lone pairs on both the S and the N).
They pass through a series of compounds to photosystem I, losing energy along the way. Photosystem I, like photosystem II, emits high-energy electrons in the light, and the electrons from photosystem II replace these. Photosystem II contains chlorophyll molecules. When a photon (quantum of light) reaches one of these chlorophyll molecules, the light energy activates an electron. This is then passed to the reaction center of the photosystem, where there are two molecules of chlorophyll P680. These pass the electrons to plastoquinone, which, like the chlorophylls, is embedded in the thylakoid membrane. The plastoquinone changes its position within the membrane, and passes the electrons to cytochromes b6 and f. At this stage the electrons part with a significant proportion of their energy, which is used to pump protons (H+) into the thylakoid lumen. These protons will later be used to generate ATP by chemiosmosis. The electrons now pass to plastocyanin, which is outside the membrane on the lumen side. Photosystem I is affected by light in much the same way as photosystem II. Chlorophyll P700 passes an activated electron to ferredoxin, which is in the stroma (the liquid outside the thylakoid). Ferredoxin in turn passes the electrons on, reducing NADP+ to NADPH + H+. Photosystem I accepts electrons from plastocyanin. So, effectively, photosystem II donates electrons to photosystem I, to replace those lost from photosystem I in sunlight. How does photosystem II recover electrons? When it loses an electron, photosystem II becomes an oxidizing agent, and splits water: 2H2O forms 4H+ + 4e- + O2. The electrons return photosystem II to its original state, and the protons add to the H+ concentration in the thylakoid lumen, for later use in chemiosmosis. The oxygen diffuses away.
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