As the earth bulges a bit at the equator, you should stand at the poles to experience the most centripetal acceleration. Looking at the formula for centripetal acceleration (Ac= v2/r), we see that as the distance from the centre of the body (r) increases, the acceleration decreases, therefore when the distance to the centre mass is smaller, as it is at the poles compared to at the equator, the acceleration is greatest.
You should stand at the top of Mount Chimborazo on the earth's surface to experience the least centripetal acceleration. This mountain is the location that is the furthest from the earth's center but it is the closest to the equator.
Constant Acceleration
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
At or near the surface of the earth, the acceleration due to gravity is 32 feet per second per second
In a vacuum it does not have any effect. In a fluid, surface area, shape and texture has great effect. A small, smooth, aerodynamically designed surface area, especially the leading surface area would aid in positive acceleration. The opposite would aid in negative acceleration.
That all depends on where you are. On the surface of the Earth, it's 9.807 . It's 1.623 on the surface of the moon, and 3.711 on Mars. (All rounded.) And it's not an "acceleration force". It's just acceleration. To get a force, you have to multiply acceleration by a mass.
Hello, To answer the question, the place where one would experience the least amount of centripetal acceleration would be at either the north or south pole. If you think about it, the part of the Earth that the spins the fastest is at the Equator. The North and South poles move the least while the Earth spins. Centripetal Force is all about making sure that a object on a spinning sphere keeps going around in a circle. If the object spins at a greater rate, the centripetal acceleration would be larger because there is more of a "pull" to keep the object in line.
The radius of the earth is 6.4 x 10^6 m. A typical orbit about 91 minutes. Show your work. Please answer this by tonight
Constant Acceleration
centripetal acceleration is described by the formula a=(v^2)/r in terms of velocity sqr(ar) = v sqr(9.8*6375000) = v v = 7904 m/s or 2.8*10^4 km/h
Because gravity is not uniform across the entire surface of the earth and the centripetal force varies noticeably with latitude, the acceleration varies from point to point on Earth. At different points on Earth, objects fall with an acceleration between 9.78 and 9.82 m/s2 depending on latitude, with a conventional standard value of exactly 9.80665 m/s2 (approx. 32.174 ft/s2).
As an object approaches the Earth's surface, what will its acceleration be?
i think that acceleration is directly proportional to surface tension.....
Centripetal force acting on an orbiting object is unbalanced since the object is being accelerated.Velocity is continually changing direction if not speed. This means an orbiting object is accelerating and the direction of acceleration is toward the center. In fact, centripetal means "center seeking."A person at rest on the surface of the Earth is being acted upon by a centripetal force (toward the center of the Earth, that is, down) which is exactly equal and opposite to the spring force of the Earth's matter pushing up. Thus, in this case, the centripetal force is balanced.The previous answer (below) is generally incorrect.No,because when a body revolves round an orbit,its CENTRIPETAL force is balanced by the WEIGHT of the body!thank you!!
if you double the earths density say , standing at the surface you would experience twice the acceleration, weight would be doubled
on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
yes