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Where should you stand on the earth's surface to experience the least centripetal acceleration Explain?
As the earth bulges a bit at the equator, you should stand at the poles to experience the most centripetal acceleration. Looking at the formula for centripetal acceleration (Ac= v2/r), we see that as the distance from the centre of the body (r) increases, the acceleration decreases, therefore when the distance to the centre mass is smaller, as it is at the poles compared to at the equator, the acceleration is greatest.
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What is the solution to the merry-go-round physics problem?
The solution to the merry-go-round physics problem involves understanding centripetal force and acceleration. The centripetal force required to keep an object moving in a circular path on a merry-go-round is provided by friction between the object and the surface of the merry-go-round. This force is directed towards the center of the circle and is equal to the mass of the object times its centripetal acceleration. By calculating the centripetal force and acceleration, one can determine the speed at which the object is moving on the merry-go-round.
What do objects in free fall near the surface of the Earth experience Constant What?
Objects in free fall near the surface of the Earth experience a constant acceleration due to gravity, which is approximately 9.81 m/s^2. This means that their speed increases at a constant rate, regardless of their mass.
How fast is g force?
"G force" is a measure of acceleration due to gravity. The acceleration due to gravity at the Earth's surface is approximately 9.8 m/s^2, so objects experience 1 g of acceleration. Astronauts may experience higher g forces during rocket launches or other maneuvers.
What occurs when objects free fall near the Earths surface constant acceleration?
When objects free fall near Earth's surface, they experience constant acceleration due to gravity. This means that the objects increase their velocity by the same amount each second while falling. The acceleration due to gravity near Earth's surface is approximately 9.8 m/s^2.
Is the acceleration due to gravity dependent on the mass of an object?
No, the acceleration due to gravity is constant regardless of the mass of an object. All objects near Earth's surface experience the same acceleration due to gravity, which is approximately 9.8 m/s^2.
Do the astronauts in the space shuttle 308 km above the surface of earth experience more or less centripetal acceleration than a person standing on the surface of earth?
The astronauts in the space shuttle experience less centripetal acceleration compared to a person standing on the surface of the Earth. This is because the centripetal acceleration experienced depends on the speed of rotation and radius of the orbit, which are greater on the surface of the Earth than in space.
Where on the surface of the earth should you stand to experience the least centripetal acceleration?
Hello, To answer the question, the place where one would experience the least amount of centripetal acceleration would be at either the north or south pole. If you think about it, the part of the Earth that the spins the fastest is at the Equator. The North and South poles move the least while the Earth spins. Centripetal Force is all about making sure that a object on a spinning sphere keeps going around in a circle. If the object spins at a greater rate, the centripetal acceleration would be larger because there is more of a "pull" to keep the object in line.
If the earth's radius is about 6375 km how fast must a satellite be moving if it is orbiting just above the earth's surface with a centripetal acceleration of 9.8ms2?
The required speed for a satellite to maintain orbit just above the Earth's surface with a centripetal acceleration of 9.8 m/s^2 is approximately 7.9 km/s. This speed is calculated using the formula for centripetal acceleration, which includes the radius of the Earth as well as the gravitational acceleration.
What is the solution to the merry-go-round physics problem?
The solution to the merry-go-round physics problem involves understanding centripetal force and acceleration. The centripetal force required to keep an object moving in a circular path on a merry-go-round is provided by friction between the object and the surface of the merry-go-round. This force is directed towards the center of the circle and is equal to the mass of the object times its centripetal acceleration. By calculating the centripetal force and acceleration, one can determine the speed at which the object is moving on the merry-go-round.
What do objects in free fall near the surface of the Earth experience Constant What?
Objects in free fall near the surface of the Earth experience a constant acceleration due to gravity, which is approximately 9.81 m/s^2. This means that their speed increases at a constant rate, regardless of their mass.
As an object approaches the Earth's surface what will its acceleration be?
As an object approaches the Earth's surface, what will its acceleration be?
How fast is g force?
"G force" is a measure of acceleration due to gravity. The acceleration due to gravity at the Earth's surface is approximately 9.8 m/s^2, so objects experience 1 g of acceleration. Astronauts may experience higher g forces during rocket launches or other maneuvers.
What is the relation between surface tension and acceleration?
i think that acceleration is directly proportional to surface tension.....
What occurs when objects free fall near the Earths surface constant acceleration?
When objects free fall near Earth's surface, they experience constant acceleration due to gravity. This means that the objects increase their velocity by the same amount each second while falling. The acceleration due to gravity near Earth's surface is approximately 9.8 m/s^2.
Is the acceleration due to gravity dependent on the mass of an object?
No, the acceleration due to gravity is constant regardless of the mass of an object. All objects near Earth's surface experience the same acceleration due to gravity, which is approximately 9.8 m/s^2.
What is the acceleration of an object approaching the earths surface?
Because gravity is not uniform across the entire surface of the earth and the centripetal force varies noticeably with latitude, the acceleration varies from point to point on Earth. At different points on Earth, objects fall with an acceleration between 9.78 and 9.82 m/s2 depending on latitude, with a conventional standard value of exactly 9.80665 m/s2 (approx. 32.174 ft/s2).
What is the experience of objects in free fall near the surface of the earth?
Objects in free fall near the surface of the Earth experience a constant acceleration due to gravity, causing them to fall towards the ground at a rate of 9.8 meters per second squared. This acceleration remains constant regardless of the object's mass, resulting in all objects falling at the same rate in a vacuum.
