Many contend that because a pendulum vibrates more rapidly in the northern region than "at the equator, the earth is thereby proved not only to be a globe, but to have axial motion, and because the variation in the velocity is that of gradual increase as the north pole is approached, it is concluded that the earth's true shape is that of an oblate spheroid--the diameter through the poles being less than that through the equator. The difference was calculated by Newton to be the 235th part of the whole diameter; or that the polar was to the equatorial diameter as 680 to 692. Huygens gave the proportion as 577 to 875, or a difference of about one-third of the whole diameter. Others have given still different proportions; but recently the difference of opinion, each the result of calculation, has become so great that many have concluded that the earth is really instead of oblate, an oblongspheroid.
It is argued that as the length of a pendulum vibrating
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
It would be closer to the Equator, but just barely. Madison, Wisconsin is about 185 miles south east of Cadott, Wisconsin. Cadott is pretty much exactly half way between the North Pole and the Equator.
The North Pole is due north of the Equator.
India is north from Equator.
Lagos is north of the equator.
Yes
A pendulum will swing slowest when closest to the equator. Why is this? The time period, T, of the swing of a pendulum is given by: T=2π√(l/g) where l is the length of the pendulum and g is acceleration due to gravity. Because the Earth is spinning, there is a bulge at the equator and the poles are slightly flattened. Hence on the equator the radius to the centre of the earth is greater than the radius at the poles. The equatorial radius is 6378.1km while the polar radius is 6356.8 km The value of g at the Earth's surface relates to the values of the Earth's radius, r, at that point using an inverse square law ie g is proportional to 1/r2 At the North Pole, g is about 9.83m/s2, while at the equator, g is smaller, at only 9.79m/s2 . So the period of a pendulum will be longer (i.e. slowest) at the equator than at the pole
It would be closer to the Equator, but just barely. Madison, Wisconsin is about 185 miles south east of Cadott, Wisconsin. Cadott is pretty much exactly half way between the North Pole and the Equator.
The North Pole is due north of the Equator.
India is north from Equator.
Lagos is north of the equator.
It is north of the equator
north of the equator
North of the equator
north of the equator
Mali is north of the equator.
It is north of the equator.