IP Address Class
Total # Of Bits For Network ID / Host ID
First Octet of IP Address
# Of Network ID Bits Used To Identify Class
Usable # Of Network ID Bits
Number of Possible Network IDs
# Of Host IDs Per Network ID
Class A
8 / 24
0xxx xxxx
1
8-1 = 7
27-2 = 126
224-2 = 16,277,214
Class B
16 / 16
10xx xxxx
2
16-2 = 14
214 = 16,384
216-2 = 65,534
Class C
24 / 8
110x xxxx
3
24-3 = 21
221 = 2,097,152
28-2 =
class A
The maximum number of host bits that can be borrowed from a class A address is 22 (technically you could borrow 23 but the resulting network would be useless). A class A address uses 8 bits for its network address and 24 bits for its host addresses. Class A uses a subnet mask of 255.0.0.0 You can only borrow 22 bits (instead of 24) because a valid network requires 4 addresses: A network address, two host addresses and a broadcast address. These networks would result in 30 bits used for the network address and 2 bits used for the host addresses. These networks use a subnet mask of 255.255.255.252
In a class A network, the first 8 bits specify the network, the remaining 24 bits specify the host.
Same as subnetting any other class, or a classless network. From the bits originally reserved for the host (16 bits, in the case of a class B address), you "borrow" some bits, that is, you use them to specify the subnet. The remaining bits specify an individual host within a subnet.
A class A address is one of the IPv4 class-full networks. There are 3 of these class-full networks in IPv4; class (A, B, and C). The entire IPv4 address range is 32 bits long. The address range is broken up into 4 x (8 bits) referred to as octets, and then giving the whole 32 bit address range. The classes are defined as follows… Class A = reserve the first octet, or 8 bits for network addresses and leave the remaining three for host addresses. Reserving the addresses for the network is also referred to as the network mask. In other words do not assign any address in the reserved, first octet, to a host. Class A = 11111111.00000000.00000000.00000000 also known as a /8 bits reserved for net Class B = 11111111.11111111.00000000.00000000 also known as a /16 bits reserved for net Class C = 11111111.11111111.11111111.00000000 also known as a /24 bits reserved for net So the answer is; a class A network has an 8 bit field for the network, and a 24 bit field for the host
62 hosts.
The network part of an IP address indicates the network to which the host belongs. The host bits or host part of an IP address points to the actual device that has an IP address on the network. It can be a computer, printer, router or any device with an IP address that has the same network part.
There are a total of 126 networks with 16,777,214 addresses per network in a Class A Address of ipv4. Such a big range Ha!
By default Class C subnet mask is 255.255.255.0 = 24 bits for network id and 8 bits for host id. in Binary 1111 1111. 1111 1111. 1111 1111. 0000 0000 Here all 1s are Network bits and all 0s are host bits. For this subnet mask you can have 256 hosts. And you can use 254 host and asign IP address to them. By Saurabh
no you can't use this IP address. you can use IP address belongs to following group only Summary of IP Address Classes Class A - 0nnnnnnn hhhhhhhh hhhhhhhh hhhhhhhh First bit 0; 7 network bits; 24 host bits Initial byte: 0 - 127 126 Class As exist (0 and 127 are reserved) 16,777,214 hosts on each Class A Class B - 10nnnnnn nnnnnnnn hhhhhhhh hhhhhhhh First two bits 10; 14 network bits; 16 host bits Initial byte: 128 - 191 16,384 Class Bs exist 65,532 hosts on each Class B Class C - 110nnnnn nnnnnnnn nnnnnnnn hhhhhhhh First three bits 110; 21 network bits; 8 host bits Initial byte: 192 - 223 2,097,152 Class Cs exist 254 hosts on each Class
The number of bits used to identify the hosts is fixed by the class of the network. Up to 24 bits can make up the host portion of a Class C address.
A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.