super conductivity
90 degrees
It does not contain unidirectional outputAnswerA purely resistive circuit is an 'ideal' circuit that contains resistance, but not inductance or capacitance.
That depends on the circuit. For a pure resistive circuit (no inductance and capacitance), the frequency will have no effect on the current.
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
90 degrees
It does not contain unidirectional outputAnswerA purely resistive circuit is an 'ideal' circuit that contains resistance, but not inductance or capacitance.
That depends on the circuit. For a pure resistive circuit (no inductance and capacitance), the frequency will have no effect on the current.
whose resistance=0,inductance=0
in a circuit of pure Resistance (r), IE. voltage source (12 v DC battery) and pure resistance (a light bulb). the voltage (v) and current (i) will be in phase. by adding capacitors and/or inductors to the circuit V and I will be pulled out of phase.
Electronic configuration of beryllium: 1s2.2s2.
Yes it is available in its pure form
yes
In a pure (ideal) capacitive circuit, current leads voltage by 90 degrees.
The term pure mixture doesn't exist; the components can be more or less pure.
laboratories
No - not naturally, it usually exist with other elements. To achieve a pure form, MnO2 needs to be heated with carbon to remove the oxygen.