Oxygen diffuse faster.
CO2 diffuses faster than O2 because it has a lower molecular weight and smaller size, allowing it to move more quickly through a medium. The exact difference in diffusion rate can vary depending on the conditions, but in general, CO2 diffuses about 20% faster than O2.
Chlorine gas diffuses the fastest among the gases listed. This is because gases with lower molar masses diffuse faster, and chlorine gas has the lowest molar mass among the options provided.
1:2, does this need explaining???? 1-O2 for every 2-SO3 thus 1:2
keq=[SO3]2[O2] [So3]2
2S + 3O2 >> 2SO3 8.0 grams O2 (1 mole O2/32 grams)(2 mole SO3/3 mole O2) = 0.1666 ( 0.17 moles SO3 ) and also, 0.1666 moles SO3 (80.07 grams/1 mole SO3) = 13.34 ( 13 grams SO3 ) if needed.
keq= [SO2]2[O2]/[SO3]2
Equation:2 SO2 + O2 --x--> 2 SO3 (x is a catalyst)
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
To balance the equation SO2 + O2 -> SO3, you need to ensure the number of each type of atom is the same on both sides of the equation. Start by adding a coefficient of 1 in front of SO2 and O2, then balance the equation by adding a coefficient of 1 in front of SO3. This balances the equation as: 2SO2 + O2 -> 2SO3.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
Oxygen (O2) diffuses the fastest in and out of body tissues due to its small size and high solubility. It is crucial for cell respiration and energy production in the body.
The balanced equation for the reaction is: 2SO2 + O2 -> 2SO3. Therefore, 1 mole of O2 is needed to react with 2 moles of SO2 to form 2 moles of SO3. So for 200 moles of SO2, you would need 100 moles of O2. At STP, 1 mole of any gas occupies 22.4 L, so the volume of O2 needed would be 2240 L (100 moles x 22.4 L).