keq= [SO2]2[O2]/[SO3]2
At STP1mol O2 = 22.4L1mol O2 = 6.022 x 1023 molecules O222.4L O2 = 6.022 x 1023 molecules O2Convert liters O2 to moles O23.36L O2 X (6.022 x 1023 molecules O2/22.4L O2) = 9.03 x 1022 molecules O2
We first calculate the molar mass of P4O10, which is 284 g/mol. Then we convert the given mass of P4O10 (142 g) to moles using its molar mass. There is a 1:4 molar ratio between P4O10 and O2 in the reaction, so we multiply the moles of P4O10 by 4 to find the moles of O2 needed.
Moles Mg = 3.00 g / 24.312 g/mol =0.123 Moles O2 = 2.20 / 32 g/mol = 0.0688 2 Mg + O2 >> 2 MgO the ratio between Mg and O2 is 2 : 1 0.123 / 2 = 0.0615 moles O2 needed we have 0.0688 moles of O2 so O2 is in excess and Mg is the limiting reactant we get 0.123 moles of MgO => 0.123 mol x 40.31 g/mol =4.96 g
If the reaction is just between O2 and Al, the balanced equation would be:3O2 + 4Al -> 2Al2O3By using the coefficients of the equation, we see that from 3 moles of O2 we get 2 moles of Al2O3. To find out how much this is in grams, we need to find the molar mass of Al2O3 . This is just the sum of the atomic masses of each atom that makes it up. (Use a periodic table to find atomic masses) So we get:26.98*2+16*3= 102.0One mole equals 102g, so the 2 moles produced by the reaction would amount to 204g.
The density of O2 at 1 atm and 20 degrees Celsius is approximately 1.429 g/L.
keq=[SO3]2[O2] [So3]2
No, the chemical equation is not balanced. The correct balanced equation is 2SO2 + O2 → 2SO3.
adding SO2
Yes, the reaction 2SO2 + O2 -> 2SO3 is a combustion reaction. This is because combustion reactions typically involve a fuel (SO2) reacting with oxygen (O2) to form a combustion product (SO3) with the release of heat and light energy.
SO2 + H20 --> H2SO3 sulphurous acid is not very stable though # The forest school, the forest school is wonderful the forest school is wonderful its filled with beer and Viagra the forest school is wonderful!!! #
In the reaction 2SO2 + O2 → 2SO3, there are 4 atoms of sulfur (S) present on the left side and 4 atoms of sulfur on the right side. There are 6 atoms of oxygen (O) on the left side and 6 atoms of oxygen on the right side.
K2CO3 (s) → K2O (s) + CO2 (g)2SO3 (g) → 2SO2 (g) + O2 (g) CaCO3 (s) → CaO (s) + O2 (g)
K2CO3 s -> K2O s plus CO2 g 2SO3 g -> 2SO2 g plus O2 g
The chemical equation for the reaction of sulfur and oxygen to form sulfur trioxide is: 2S + 3O2 -> 2SO3
Its balancing is very simple, 2SO2 + O2 = 2SO3
The molar ratio of O2 to SO2 in the reaction 2SO2 + O2 -> 2SO3 is 1:1. This means that one mole of O2 reacts with two moles of SO2 to produce two moles of SO3.
1,8 moles of oxygen are necessary.