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If the reaction is just between O2 and Al, the balanced equation would be:
3O2 + 4Al -> 2Al2O3
By using the coefficients of the equation, we see that from 3 moles of O2 we get 2 moles of Al2O3. To find out how much this is in grams, we need to find the molar mass of Al2O3 . This is just the sum of the atomic masses of each atom that makes it up. (Use a Periodic Table to find atomic masses) So we get:
26.98*2+16*3= 102.0
One mole equals 102g, so the 2 moles produced by the reaction would amount to 204g.
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How many moles of CaBr are in 5.0 grams of CaBr2?
To find the number of moles of CaBr2 in 5.0 grams, you first need to calculate the molar mass of CaBr2. The molar mass of CaBr2 is 200.8 g/mol. Divide the given mass by the molar mass to find the number of moles: 5.0 g / 200.8 g/mol = 0.025 moles of CaBr2. Since there is one mole of CaBr2 for every two moles of CaBr, you have half of that amount in moles of CaBr: 0.025 moles / 2 = 0.0125 moles of CaBr.
How many moles are present in 355 grams of Au?
To find the number of moles in 355 grams of Au, you need to divide the given mass by the molar mass of gold (Au). The molar mass of Au is approximately 197 grams/mol. Therefore, 355 grams of Au is equivalent to 355/197 = approximately 1.80 moles of Au.
How many moles are in 42 grams of CO2?
To calculate the number of moles in 42 grams of CO2, we first need to find the molar mass of CO2, which is approximately 44 grams per mole. Then, divide the given mass by the molar mass to find the number of moles. In this case, 42 grams of CO2 is equivalent to 42/44 = 0.955 moles.
How many grams of fructose are in 1.20 moles of fructose?
The molar mass of fructose is approximately 180.16 g/mol. To find the mass in grams, you would multiply the number of moles (1.20 mol) by the molar mass (180.16 g/mol). Therefore, 1.20 moles of fructose would be 216.19 grams.
How many moles of K2SO4 are in 15.0 grams of K2SO4?
To find the number of moles of K2SO4 in 15.0 grams, first calculate the molar mass of K2SO4 (K: 39.10 g/mol, S: 32.07 g/mol, O: 16.00 g/mol). Molar mass of K2SO4 = 2(39.10) + 32.07 + 4(16.00) = 174.26 g/mol Now, divide the given mass by the molar mass to find the number of moles: 15.0 g / 174.26 g/mol = 0.086 moles of K2SO4
How many moles of aluminum oxide ( Al2O3) are formed in the reaction Fe2O3 2Al-Al2O3 2Fe?
In the given reaction, the stoichiometry is 1:1 for Fe2O3 to Al2O3. So the number of moles of Al2O3 formed will be the same as the number of moles of Fe2O3 originally present.
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
How many moles of Al203 are formed when 0.78mol o2 reacts with aluminium?
The balanced reaction equation is 4Al + 3O2 -> 2Al2O3. Therefore, 3 moles of O2 reacts with 4 moles of Al to form 2 moles of Al2O3. Since 0.78 mol of O2 is reacted, the number of moles of Al2O3 formed can be calculated using the stoichiometry of the reaction.
How many aluminum atoms are in 291.257 grams of Al2O3?
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
How many grams of oxygen are in 5.75 moles of aluminum oxide?
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many moles og Al are in 2.16 mol of Al2O3?
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
How many moles of Al2O3 are present in 49.3 g of this compound?
To find the number of moles, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Divide the given mass (49.3 g) by the molar mass to get the number of moles of Al2O3 present. 49.3 g / 101.96 g/mol ≈ 0.483 moles of Al2O3.
If 76 grams of Cr 2 O 3 and 27 grams of Al react to form 51 grams of Al 2 O 3 how many grams of Cr are formed?
To find the mass of Cr formed, we first need to calculate the initial moles of Cr2O3 and Al. Next, we determine the limiting reactant based on stoichiometry. Knowing Al is the limiting reactant, we calculate the theoretical yield of Al2O3 formed, and then find the amount of Cr formed based on the stoichiometry of the reaction.
How many grams of aluminum oxide is formed when 6.4 grams of aluminum is reacted?
To answer this first of all you need to know the equation of the reaction. 4Al + 3O2 ----> 2Al2O3 Then you need to know how many moles of aluminium you have mass = moles x molecular weight, therefore: moles = mass/ molecular weight. 38.8/21 = 1.85 (with rounding). This is the number of moles of aluminium you have. To work out how much oxygen is added you need to take the ratio of moles(O2:Al) from the equation (3/4 or 0.75) and multiply by the number of moles of aluminium 1.85 x 0.75 = (5.55/4). This is the number of moles of oxygen. I left it like this as it will be nicer to multiply out later. As you want the final mass you need to find the mass of oxygen added to the aluminium using mass = moles x molecular weight from before except as there are two oxygen atoms per molecule so the number needs to be doubled. (5.55/4) x (16 x 2) = 44.4g. This how much oxygen is added in the creation of aluminium oxide. To get the final total you add the amount of aluminium to the amount of oxygen added 38.8g + 44.4g = 83.2g
If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
