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No, your live (brown) cable takes the load and pulls the amps from the supply, not the neutral. Your ammeter should be clipped on the live to get a correct reading.
An ammeter is placed in series with a circuit in order to measure the current. If it has any appreciable resistance, inserting the ammeter will increase the normal resistance of the circuit and reduce the value of the current flowing through it. The ammeter will, therefore, give an inaccurate reading (under-read). So the ammeter must have a very low resistance so that it has the minimum effect on the normal resistance of the circuit being tested. Ideally, the ammeter should have zero resistance but, of course, this is impossible.
That would have to be a 'wattmeter', but they're seldom available. In terms of more readily available instruments, you'd need to use a voltmeter, reading the battery's voltage, and an ammeter inserted in series in one of the battery's connections, reading the current from the battery. The rate at which the battery is supplying energy at any moment is then the product of the two meter readings.
The internal resistance of an ideal voltmeter is infinity ohms. The internal resistance of an ideal ammeter is zero ohms. Since there are no ideal voltmeters or ammeters, we consider the error introduced by adding these instruments to various circuits. In general, practical meters have high enough impedance (voltage) or low enough impedance (current) to not affect the reading more than the instruments accuracy specification, or to not affect the circuit more than is considered acceptable. There are times when this is not true, so we always consider the instrument and its contribution to systemic error.
A dominant reading also known as an invited reading, is the desired effect of the text such as an advertisement. It is the most 'obvious' reading of the text according to the dominant stereotypes.
An ammeter or a voltmeter gives the reading of the flow of current, which is due to the movements of ions. When a rusted nail is immersed in the solution it will add the no of ions into the solution. This will increase the ion concentration and therefore will change the reading of a voltmeter and ammeter.
The current decreases due to I=V/R. The ammeter reading will decrease as R is increased.
the bulb will glow and ammeter will show the reading
Assuming the new lamp is in series, the ammeter reading falls because the total resistance has increased. By how much depends on how the lamp resistance depends on voltage. If the lamp is added in parallel to the first, then the ammeter reading doubles.
v on a ammeterusually means Volts
the universal solvent is water. and it can not dissolve most carbonates most oxides a few chlorides lead sulphate ,lead iodide, lead chloride barium sulphate, calcium sulphate most metals. I have not listed all of the insoluble materials here just a few. thanks for reading.
An open switch in a circuit will stop all current flow so the ammeter should read zero amps.
Connecting an ammeter does not reduce the frequency errors.
The voltage remains the same across the circuit as it is a parallel connection. So, the current across the upper half of the circuit where the ammeter is connected is calculated as I = V/R = 12.04 (total voltage)/12 (Resistance R1) = 1 A. Hence, the ammeter will read 1 A.
You have to do the experiment you have been asked to do to find out.
The answer to this depends on where the ammeter is in the circuit. Assuming the ammeter is in series with the bulb and no other objects are attached, then the current is 0.4 Amps. Otherwise, your question is unanswerable without more information.
No, your live (brown) cable takes the load and pulls the amps from the supply, not the neutral. Your ammeter should be clipped on the live to get a correct reading.