The highest energy photons are all found at the "top" of the electromagnetic spectrum. That's the end populated by photons with the shortest wavelengths (and, therefore, the shortest periods) and the highest frequencies. These photons, these extremely energetic electromagnetic waves, are generated within the nuclei of atoms and released during nuclear events. Subatomic particles actually generate the photons as they go through changes. Stars (most of them) can produce photons in these energies continuously, or in bursts. We frequently refer to photons of extreme energies as gamma rays. We can stimulate nuclei to generate these high energy photons in the nuclear physics laboratory, and it's usually done with some sort of nuclear accelerator. We take protons - or whole atomic nuclei - and speed them up to near light speed and slam these nuclear bullets into targets (or other particles). Photons of the highest energies are produced. As one can imagine, shielding for containment is a big concern, as these energetic photons will punch through steel, concrete and earth. Some links are provided.
The higher the frequency of the EM radiation, the greater the energy of an individual photon.
X-rays have far higher frequencies than do radio waves.
The highest-energy photons are called gamma rays.
More frequence = more energy.
I think it is because a photon has less energy that is why it has less ability than a gamma ray photon
The photon (quantum) at gamma frequency has more energy than a photon at microwave frequency has. But you can easily generate a beam of microwaves carrying more energy than, for example, the gamma rays that enter your house from space. Just use a more powerful source of microwaves to generate more photons. No big deal. The one in your kitchen that you use to heat the leftover meatloaf pours out far more energy every second than gamma rays bring into your house, but each microwave photon carries much less energy than a gamma photon does.
Each photon of blue light has more energy than a photon of any other color, because the blue ones have the highest frequency.
Yes, due to the energy of photons/electromagnetic particles being determined by the equations below: E= hv=hc(1/v)= hc/wavelength. Where E= energy, v= frequency in Hz, h= Planck's constant, c= speed of light Electrons have a very short wavelength, and a very high frequency, thus they have much more energy than a beam of light.
An X-ray proton. This is so because the x-ray has much higher frequency and shorter waves.
The energy of a photon is inversely propotional to its wavelength. The wavelength of a blue photon is less than that of a red photon. That makes the blue photon more energetic. Or how about this? The energy of a photon is directly proportional to its frequency. The frequency of a blue photon is greater than that of a red photon. That makes the blue photon more energetic. The wavelength of a photon is inversely proportional to its frequency. The the longer the wavelength, the lower the frequency. The shorter the wavelength, the higher the frequency.
Nope. Radio waves have a long wavelength, which causes them to carry little energy. For future questions about energy and waves, use the formula E=h(c/lambda). E is the energy of the wave, h is plank's constant, c is the speed of light (3x10^8), and lambda is the frequency. Have fun! ^_^
The radio spectrum for communications spans approximately from 150 kHz to 26 MHz. The visible light frequency range is at least 400 THz. No contest -- visible light is at least 15 million times higher in frequency. Energy = Planck's constant * frequency. Hence visible light carries a higher energy.
More frequence = more energy.
More energy per photon than visible light, if that's what you mean.
It does not. A photon has no rest mass an electron has mass and therefore more energy
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
Yes. Energy is inversely proportional to wavelength. Shorter wavelength = more energetic.
The higher the frequency, the more excited the photon stream.
The smaller the wavelength (high frequency), the higher the energy. So gamma has the highest energy, followed by x-rays, UV, visible, infrared, microwaves, radio, in descending order. This is also why green laser-pointers are more expensive than red ones ;)
The higher the frequency the more energy per photon.