Chlorine dioxide has a bent shape. It is very interesting in that one Cl-O bond is a double bond, and the other is a single bond with three electrons. Refer to the related links for the Wikipedia article on this compound.
Assuming that the compound is the one that should have been written as Ca(ClO3)2, the answer can be determined by counting in a properly interpreted formula: one Ca, two Cl, and six O for a total of nine.
Bioinorganic elements are H, O, N, C, Na, P, S, Cl, K, Ca, Fe, Mn, Cr, Co, Cu, Zn, Se, I; not still confirmed role: B, Ge, V, Si.
HCl is a compound, C, O, Hg are elements
The order is: O, Cl, Sb, Rb, Ar.
OCl2 is covalent compound and the bond between O and Cl is covalent
The aluminum ion is Al3+ and the sulfide ion is S2-. The formula for aluminum sulfide is Al2S3. In an ionic compound, the size of the charge of each ion becomes the subscript on the opposite ion. This is called the crisscross rule. https://www.youtube.com/watch?v=99NVKAss5LE&t=240s
This compound is potassium oxide, K2O.
H3C is a part of the larger compound H3C-CH2-O-CH3, which is ethyl methyl ether, also known as methoxyethane.
Chemical formula foe chlorine monoxide is Cl2O. It is made of elements Cl and O. So it is a compound.
H3C is a part of the larger compound H3C-CH2-O-CH3, which is ethyl methyl ether, also known as methoxyethane.
It is a compound, it has no valency. The Cr in it has a valency of +7
magnesium and fluorine will formthe ionic compound, MgF2
K2Cr207
There are three elements that make up the compound beryllium chromate: Be = beryllium Cr = chromium O = oxygen
You do this For EX: _HCl + _MgO -> _H2O + _MgCl2 Mg-1 H-2 Coefficient O-1 Mg-1 | H-1 Cl-1 V Cl-1 O-1 EX: 2HCl + MgO -> H2O + MgCl2 Mg-1 H-2 O-1 Mg-1 H-2 -- Cl-2 Cl-2 --Mark out O-1 out and replace And then your done....
CO2 is a covalently bonded compound, taking the form of O=C=O, with two pairs of electrons on each oxygen atom. Ionic compounds involve ionic bonds, such as that of NaCl (Na+ and Cl-).