They are equivalent. Molal is now an obsolete, not recommended term.
A 1 molar solution of sodium chloride contain 58,44 g NaCl in 1 L water.
kcl...more reactive
The molar mass of NaCl is 58.44 g/mol The molar mass of KCl is 74.5513 g/mol This is because the Potassium atom (K) is heavier than the Sodium atom (Na). Thus one gram of NaCl will contain more molecules (formula units) than one gram of KCl.
There are more than 2 kinds, but perhaps you refer to molar (M) and molal (m). Or maybe you refer to weigh/volume and weight/weight. Or, maybe even you refer to % by mass and % by volume. And there are still others.
There is reaction when more or less concentrated H2SO4 is used on NaCl(BE VERY CAREFULL, only in laboratory circumstances). HCl (gas!) is toxic and very dangerous.H2SO4 + NaCl --> HCl(gas) + Na2SO4
NaCl
Molal is the number of mols of solute per kilo of solvent. Molar is the number of mols of solute per litre of solution. If you think those through, you should see that which is greater depends on the density of the solvent.
* 50 g salt/100 g water is a more concentrated but a saturated sodium chloride solution (the solubility of NaCl at 20 0C is approx. 36 g/100 mL). * 18 g salt/90 g water is a 20 % sodium chloride solution.
It is less concentrated than in the USA, but more concentrated than in Europe.
* 50 g salt/100 g water is a more concentrated but a saturated sodium chloride solution (the solubility of NaCl at 20 0C is approx. 36 g/100 mL).* 18 g salt/90 g water is a 20 % sodium chloride solution.The first solution is more concentrated.
* 50 g salt/100 g water is a more concentrated but a saturated sodium chloride solution (the solubility of NaCl at 20 0C is approx. 36 g/100 mL).* 18 g salt/90 g water is a 20 % sodium chloride solution.The first solution is more concentrated.
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
concentrated