Without the lone pairs of electrons, it would be
F -- O -- F
Based on it's electronegative difference the kind of bond present in the compound OF2 is a Polar covalent bond.
As I originally stated in my original answer, the bonds in a molecule of OF2 are covalent. The electronegativity difference between them, according to the Pauling values is 0.54, which indicates a slightly polar covalent bond, in which Fluorine has the higher electronegativity value.
OF2 is covalent.
a covalent bond between two atoms
2
Based on it's electronegative difference the kind of bond present in the compound OF2 is a Polar covalent bond.
As I originally stated in my original answer, the bonds in a molecule of OF2 are covalent. The electronegativity difference between them, according to the Pauling values is 0.54, which indicates a slightly polar covalent bond, in which Fluorine has the higher electronegativity value.
The bond between O and F would be a covalent bond (dative/coordinate), if in fact OF existed. More likely it would exist as OF2 (still covalent bonds).
OF2 is covalent.
a covalent bond between two atoms
Atoms with a covalent bond
2
It is covalent, as are nearly all compounds consisting of only nonmetals.
No, OF2 is covalent
OF2 is covalent. Both elements O and F are nonmetals. They would both form negative ions which would not attract each other.
OF2 is oxygen difluoride, a very powerful oxidizer.
Since the covalent bond between sulfur and oxygen is polar, dipole dipole attractions are present as intermolecular forces.