-1.95
-1.95
-1.95V
-1.95
The reduction potential of Na is -2.71 V and the reduction potential of Zn is -0.76 V. When Na is reduced, it gains electrons, so its reduction potential is written as a positive value (+2.71 V). When Zn is oxidized, it loses electrons, so its oxidation potential is -0.76 V. Therefore, the total reduction potential of the cell is +2.71 V - (-0.76 V) = +3.47 V.
-1.95V
In this reaction, sodium is being oxidized. When sodium reacts with chlorine gas, sodium atoms lose electrons to form sodium ions, and this process involves the loss of electrons, which is characteristic of oxidation.
When phenol is treated with sodium borohydride, a reduction reaction occurs and the oxygen atom in the hydroxyl group of phenol gets reduced to a hydroxide ion. This reaction usually leads to the formation of cyclohexanol as the main product.
An exothermic reaction will occur, with the peroxide being reduced and the thiosulfate being oxidized.
Sodium ions are reduced to form sodium metal because sodium has a lower reduction potential than calcium. This means it requires less energy to convert sodium ions into sodium metal compared to calcium ions into calcium metal. The presence of CaCl2 in the fused NaCl helps lower the melting point of NaCl, making the electrolysis process more efficient.
It is a REDOX reaction. Sodium is oxidized by Fluorine which is itself reduced by the sodium. 2Na + F2 = 2NaF.
The reduction potential of sodium borohydride is approximately -1.24 V versus the standard hydrogen electrode (SHE). This makes it a strong reducing agent commonly used in organic chemistry for the reduction of aldehydes, ketones, and other functional groups.
Yes, bromine will react with sodium. When bromine comes in contact with sodium, they will react to form sodium bromide, a white solid compound. This reaction is a redox reaction where bromine gets reduced and sodium gets oxidized.