You want "Either of X and Y." X and Y are a set, and you are picking one out of the set.
One by one: char x; char y; & both together char x,y;
When dividing one integer with another, there's a high probability that the answer will not be an integer. To deal with this, you must cast the numerator or denominator to a floating point type (float or double). By way of an example, consider the following code snippet: int x=5, y=2; int z = x/y; float f1 = x/y; float f2 = ( float ) x/y; float f3 = x/( float ) y; printf( "x=%d, y=%d, z=%d, f1=%f, f2=%f, f3=%f\n", x, y, z, f1, f2, f3 ); Output: x=5, y=2, z=2, f1=2.000000, f2=2.500000, f3=2.500000 Clearly the correct answer is shown by f2 and f3. This is because we explicitly cast the numerator or denominator in each case. So long as we cast one or the other (or both), the result will be correct. If we don't cast either, then we're effectively only converting the result of the integer division, which is effectively the same as casting z to a float, as shown by f1. See the related links section for in-depth information on floating point arithmetic in C/C++.
Commutative x + y = y + x x . y = y . x Associative x+(y+z) = (x+y)+z = x+y+z x.(y.z) = (x.y).z = x.y.z Distributive x.(y+z) = x.y + x.z (w+x)(y+z) = wy + xy + wz + xz x + xy = x x + x'y = x + y where, x & y & z are inputs.
The quality operator and the assignment operator are binary operators; they have two operands, one on either side of the operator. The equality operator is a Boolean operator which compares the two operands, returning true if they have the same logical state, otherwise false. E.g., x==y returns true if x and y have the same logical state, otherwise false. The operator is commutative, such that x==y is the same as y==x. The assignment operator sets the value of the left operand to that of the right operand, such that they both have the same logical state. After assignment, the left operand is returned. E.g., x=y returns x while y=x returns y. After the assignment, x==y must be true.
Genetic disorders that are linked to either the X or the Y chromosomes. Red-green colorblindness and hemophilia are both sex-linked disorders.
Short answer: Yes. Long answer: it depends on the order. If x is negative and y is positive, then x-y<0; y-x>0 (this second one is only correct if |y|<>|x|). And if |y|=|x| then y-x=0 (this is the one you're looking for, where x and y are equal, but y is positive and x is negative). Finally, if you know if |y|=|x| or |y|<>|x| then y-x>=0
16
X + Y⁶X + Y * Y * Y * Y * Y * Y
(x,y). x axis first, the one that goes horizantial. Then your y axis, which is the vertical one
y=x+2 is also equal to y-2=xy = x + 2 , they have to be given what either x or y is and then you'd solve for the other one
Half correct because x = 2 and y = 6
The assertion in the question is false. The result of a multiplication depends on the values. Given two numbers X and Y, if X < 0 and if Y < 0 then X*Y is greater than either; if X > 1 and if Y > 1 then X*Y is greater than either; if X < 0 and if Y > 1 then X*Y is smaller than either; if X > 1 and if Y < 0 then X*Y is smaller than either; if 0 < X < 1 and if 0 < Y < 1 then X*Y is smaller than either; If X < 0 and if 0 < Y < 1 then X*Y is greater than X but smaller than Y; If 0 < X < 1 and if Y > 1 then X*Y is greater than X but smaller than Y; If 0 < X < 1 and if Y < 0 then X*Y is smaller than X but greater than Y; If X > 1 and if 0 < Y < 1 then X*Y is smaller than X but greater than Y.
You can work this out by solving one of the equations for either of the variables, and substituting that solution for that variable in the other equation. That will give you one either the X or Y co-ordinate for the point of intersection, and you can calculate the other one with one by plugging that back into one of the original equations: y = x + 4 y = 3x ∴ 3x = x + 4 ∴ 2x = 4 ∴ x = 2 y = 3x ∴ y = 6 So the point of intersection between the lines y = 3x and y = x + 4 is (2, 6).
Either - or both - can be true.
x times y or, symbolically, either x*y or simply xy (where context allows, also X x Y)
Females carry the XX Chromosome and Males Carry The XY chromosome A sex cell contains half of this chromosome (so for Me either X or Y and for women either one of the Xs). There for it is the mans sperm with determines the sex of the child as a woman can only give X where as a male can give either X or Y. X to have a girl and Y for a boy.
All chromosomes that are not either X or Y are called autosomes.