co2
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
What is 'ch4'? If you mean 'CH4' , then the balanced symbol eq'n is CH4 + 2O2 = CO2 + 2H2O I question your 'ch4' because all single letter elemental symbols are ALWAYS a capital letter. This is the international IUPAC standard , that appears in the Periodic Table. Lower/small case letters are only used for two letter symbols, where the second letter is lower case. e,g, sodium 'Na'.
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that one molecule of methane (CH4) reacts with two molecules of oxygen (O2) to produce one molecule of carbon dioxide (CO2) and two molecules of water (H2O). This is a combustion reaction where methane is burned in the presence of oxygen to produce carbon dioxide and water.
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
CH4 --> CO2 is a 1 to 1 reaction (C-balanced) when burning with oxygen. So 1 mole CH4 --> 1 mole CO2 So 1 Litere CH4 --> 1 Liter CO2 So 16 grams CH4 --> 44 grams CO2