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101010100 010101011

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Q: Which one of the followings is transmittable data for data units 10101010 01010101 if system uses odd party?
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Which is transmittable data for data units 10101010 01010101 if system uses odd party?

101010100 010101011


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What is the hexadecimal equivalent of the ethernet address 010111010 00010001 01010101 00011000 10101010 00001111?

This should be an invalid MAC address because the first octet is 9 bytes long. However it converts out to BA:11:55:18:AA:F. However this is not a real MAC address since the OUI (first three octets are not registered to any corporation.) Here are the results of your search through the public section of the IEEE Standards OUI database report for BA:11:55: Sorry! The public OUI listing contains no match for the query BA:11:55If you want to know the math behind it it becomes tricky. Hex is a 16 base system. We're used to a 10 base system 0-9. Hex runs 0-16 so it counts like this0=01=12=23=34=45=56=67=78=89=9A=10B=11C=12D=13E=14F=15 So to count by Hex 0F would =15Then 10 would = 16. You cannot look at it like a ten, it is a one, zero. that's one group of 16 and 0 ones. So 20 (two zero) would equal 32 (two sixteens)With the basics of hex we can convert the binary to decimal.To count by binary we once again have to thing a bit differently. while they look like a bunch of ones and zeros they each stand for a different number with each place multiplying the previous number by 2. So it counts 1,2,4,8,16,32,64,128. Only it is read right to left 128,64,32,16,8,4,2,1 The binary number 10101010 can be calculated like this 128 64 32 16 8 4 2 11 0 1 0 1 0 1 0 So that is one of each 128,32,8,2128+32+8+2=170 to convert this 170 to hex we can devide it by 16 170/16=10.625That gives us 10 full groups of 16 which is a Hexidecimal (A) or 160. This leaves us with a remainder of 10, which we know is another (A). So the Hex for 10101010 = AA


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