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BaBr2 has two ionic bonds, but no covalent bonds.
Its nonpolar :)
BaBr2
Formula: BaBr2
Ba + Br2 ----> BaBr2
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
Barium bromide is ionic.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
BaBr2
BaBr2 + 2HCl >> BaCl2 + 2HBr
Ba2Ba4 is technically correct, it's just that it would reduce to BaBr2