No, BaBr2 is a crystalline solid compound that forms a specific lattice structure, making it difficult to shape or mold into different forms. Its rigid structure gives it a fixed characteristic shape at the atomic level.
The skeleton equation for the reaction between barium and bromine would be: Ba + Br2 -> BaBr2.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
Barium bromide is an inorganic compound composed of barium and bromine, with the chemical formula BaBr2. It is a white crystalline solid and is commonly used in a variety of applications, including as a precursor in organic synthesis and in the production of specialty glass.
The formula for barium bromide is BaBr2. This compound consists of one barium ion (Ba^2+) and two bromide ions (Br^-).
No, BaBr2 is a crystalline solid compound that forms a specific lattice structure, making it difficult to shape or mold into different forms. Its rigid structure gives it a fixed characteristic shape at the atomic level.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
BaBr2
The skeleton equation for the reaction between barium and bromine would be: Ba + Br2 -> BaBr2.
BaBr2 + 2HCl >> BaCl2 + 2HBr
BaBr2 does not contain any covalent bonds. It is an ionic compound composed of barium cations (Ba2+) and bromide anions (Br-), which are held together by ionic bonds formed through the transfer of electrons.
Yes, BaBr2 is an ionic compound. It consists of barium (Ba), a metal, and bromine (Br), a nonmetal. In BaBr2, barium loses two electrons to become a cation (Ba2+), while bromine gains one electron from each barium atom to form an anion (Br-), resulting in an ionic bond between them.
14.17 mol BaBr2 has 2*14.17 mol Br in it, so 28.34 mol KBr can be produced (also 28.34 mol K is needed)
2 KBr + BaI2 ----> 2 KI + BaBr2
Barium bromide is an inorganic compound composed of barium and bromine, with the chemical formula BaBr2. It is a white crystalline solid and is commonly used in a variety of applications, including as a precursor in organic synthesis and in the production of specialty glass.