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When was James V. Hart born?
James V. Hart was born in 1960.
What are the ratings and certificates for Hart and Soul The Hart Family Anthology - 2010 V?
Hart and Soul The Hart Family Anthology - 2010 V is rated/received certificates of: Australia:M
How would you evaluate the indefinite integral -2xcos3xdx?
Integrate by parts: ∫ uv dx = u ∫ v dx - ∫ (u' ∫ v dx) dx Let u = -2x Let v = cos 3x → u' = d/dx -2x = -2 → ∫ -2x cos 3x dx = -2x ∫ cos 3x dx - ∫ (-2 ∫ cos 3x dx) dx = -2x/3 sin 3x - ∫ -2/3 sin 3x dx = -2x/3 sin 3x - 2/9 cos 3x + c
How do you solve derivatives?
There are several ways to solve for the derivative:You can use the limit definition: limhà0=(f(x+h)-f(x))/h.You can use the limit at a point definition (when you actually have a point, or if not use #1): limx->a=(f(x)-f(a))/(f-a).Use the short cuts:The derivative of a constant like 2 or pi is 0.For things raised to a power: d/dx(xn)=nxn-1 where n is any real number.Multiplying by a constant, multiply the derivative of u by the constant c: d/dx(cu)=c*du/dxAdding, you add the derivative of the first part and the derivative of the second: d/dx(u+v)=du/dx+dv/dxSubtracting, you subtract the derivative of the first part and the derivative of the second: d/dx(u-v)=du/dx-dv/dx(Multiplying and dividing are more complicated, and you'll just have to memorize their formulas)Multiplying, the formula is: d/dx(uv)= u*dv/dx+v*du/dxDividing, the formula is: d/dx(u/v)=(v*du/dx-u*dv/dx)/(v2)d/dx(v/u)=(u*dv/dx-v*du/dx)/(u2)
What is the sum rule?
d/dx (u + v) = du/dx + dv/dx essentially this means that if you are finding the derivative of two functions u and v that you can find the derivative of each function separately and then add the derived functions to get the answer.
What is the equstion to velocity?
v=dx/dt, where v= velocity x=displacement t=time
Integration by parts of x tanx?
XtanX dx formula uv - int v du u = x du = dx dv = tanX dx v = ln(secX) x ln(secX) - int ln(secx) dx = X ln(secx) - x ln(secx) - x + C -----------------------------------------
How do you integrate the function x square e to the power x?
By using: ∫uv = u∫v - ∫u'∫v twice. ∫x2exdx let u = x2, v = ex, then: ∫x2exdx = x2∫exdx - ∫d/dx(x2)∫exdx dx = x2ex - ∫2xexdx Again, let u = 2x, v = ex, then: = x2ex - (2x∫exdx - ∫d/dx(2x)∫exdx dx) = x2ex - 2xex +∫2exdx = x2ex - 2xex + 2ex + C
What are the ratings and certificates for 1PW Teddy Hart - In His Words - 2006 V?
1PW Teddy Hart - In His Words - 2006 V is rated/received certificates of: UK:E
What are the ratings and certificates for Bret 'Hit Man' Hart - 1996 V?
Bret 'Hit Man' Hart - 1996 V is rated/received certificates of: UK:E
What is the second derivative of x ln x?
f(x)=xln(x) this function is treated as u*v u=x v=ln(x) The derivative of a product is f'(x)=u*v'+v*u' plugging the values back in you get: f'(x)=(x*dlnx/x)+(ln*dx/dx) The derivative of lnx=1/x x=u dlnu/dx=(1/u)*(du/dx) dx/dx=1 x=u dun/dx=nun-1 dx1/dx=1*x1-1 = x0=1 f'(x)=x*(1/x)+lnx*1 f'(x)=1+lnx Now for the second derivative f''(x)=d1/dx+dlnx/dx the derivative of a constant, such as 1, is 0 and knowing that the derivative of lnx=1/x you get f''(x)=(1/x)
What is the Integral of 23x e2x dx?
This browser is pathetic for mathematical answers but here's the best that I can do:Let u = 23x therefore du/dx = 23let dv/dx = e^(2x) therefore v = 1/2*e^(2x)then, integrating by parts,I = I(u*dv/dx) dx = u*v - I(du/dx*v) dx= 23x*(1/2)*e^(2x) - I(23*(1/2)*e^(2x) dx= 23/2*xe^(2x) - 23/2*I(e^(2x)) dx= 23/2*xe^(2x) - 23/2*(1/2)*e^(2x)= 23/2*xe^(2x) - 23/4*e^(2x)or 23/4*e^(2x)*(2x - 1)
