Alkenes have pi bonds that are readily available to react because the strength of a pi bond isn't as strong as a sigma bond. Pi electrons will attack the nucleophile to form the respective carbocation. Alkanes only contain sigma bonds and have no pi electrons to attack a nucleophile. In order for an alkane to become a strong enough nucleophile it must not be sterically hindered (primary carbons prefered to tertiary) and most likely deprotenated by a very strong base ( likely stronger than sodium amide ).
Alkynes undergo many addition reactions such as: catalytic hydrogenation, addition by electrophilic reagents, hydration with tautomerism, hydroboration reactions, and oxidations. They also undergo nucleophilic addition reactions & reduction. Finally alkynes are the strongest bronsted acids made from only hydrocarbons.
The addition of hydrogen on alkenes produces the alkanes so it is a reduction process.
Alkenes, or hydrocarbons with at least one double bond undergo an addition reaction when combined with bromine (Br2). The general reaction is H2C=CH2 --> H2BrC--CBrH2, and it occurs readily. This reaction is a good way to identify alkenes because bromine has a reddish color, while alkanes and alkenes are colorless. So if bromine is added to an unknown hydrocarbon, the disappearance of the color is an indication of the presence of a pi bond.
Alkenes have at least one double bond between two carbon atoms; alkanes don't.
Single bond
No, bromine will only add to alkenes, so NO addition reaction to alkanes. Subtitution on alkanes is not possible at standard conditions
Alkynes undergo many addition reactions such as: catalytic hydrogenation, addition by electrophilic reagents, hydration with tautomerism, hydroboration reactions, and oxidations. They also undergo nucleophilic addition reactions & reduction. Finally alkynes are the strongest bronsted acids made from only hydrocarbons.
alkanes
alkenes are neutral nucleofiles they undergoes electrophilic addition reactions.
Bromine water can test the difference between alkanes and alkenes because the bromine water turns colourless for the alkenes but doesnt change for the alkanes.
The addition of hydrogen on alkenes produces the alkanes so it is a reduction process.
Alkanes are saturated hydrocarbons. Alkenes are unsaturated hydrocarbons with atleast one carbon-carbon double bond.
alkanes have single covalent bons, alkenes have double :) lol did this while doing chem homework myself
Saturated oils and waxes are all types of alkanes and alkenes The Ice man ;) Call me ladies... ;')
Alkenes have pi bonds that are readily available to react because the strength of a pi bond isn't as strong as a sigma bond. Pi electrons will attack the nucleophile to form the respective carbocation. Alkanes only contain sigma bonds and have no pi electrons to attack a nucleophile. In order for an alkane to become a strong enough nucleophile it must not be sterically hindered (primary carbons prefered to tertiary) and most likely deprotenated by a very strong base ( likely stronger than sodium amide ).
Alkenes, or hydrocarbons with at least one double bond undergo an addition reaction when combined with bromine (Br2). The general reaction is H2C=CH2 --> H2BrC--CBrH2, and it occurs readily. This reaction is a good way to identify alkenes because bromine has a reddish color, while alkanes and alkenes are colorless. So if bromine is added to an unknown hydrocarbon, the disappearance of the color is an indication of the presence of a pi bond.
cracking maybe?