The lone pair on the nitrogen of aniline is delocalised into the pi-system of the benzene ring and is therefore less available for attack on a proton.
Aniline is a weaker base than ammonia because the lone pair on the nitrogen atom in aniline is partially delocalized into the benzene ring, making it less available for donation to form a bond with a proton. In contrast, the lone pair on the nitrogen atom in ammonia is more readily available for donation, resulting in a stronger basicity.
Yes. Ammonia has a pKb of 4.75. Water has a pKb of 13.995.
Neither is an acid. Both are bases, hydroxide is the stronger base.
Cyclohexylamine is a stronger base than aniline because the nitrogen atom in cyclohexylamine is less hindered by bulky substituents than in aniline. This allows for easier access of the lone pair of electrons on nitrogen in cyclohexylamine, making it more available for proton transfer. Aniline's lone pair is more delocalized into the benzene ring, which reduces its basicity.
Sodium hydroxide is a stronger base compared to ammonia. This is because sodium hydroxide has a higher dissociation constant (pKa) and is more effective at donating hydroxide ions in solution, resulting in a higher pH compared to ammonia.
Aniline is a weaker base than ammonia because the lone pair on the nitrogen atom in aniline is partially delocalized into the benzene ring, making it less available for donation to form a bond with a proton. In contrast, the lone pair on the nitrogen atom in ammonia is more readily available for donation, resulting in a stronger basicity.
Yes. Ammonia has a pKb of 4.75. Water has a pKb of 13.995.
Neither is an acid. Both are bases, hydroxide is the stronger base.
Since tha pka of the aniline ion is equal to 4.6, the anilinium ion is a stronger acid than the methylaminium ion, and aniline (c6h5nh2) is a weaker base than methylamine (ch3nh2).
in the case of aniline, the lone pair on nitrogen is involved in resonance with the benzene ring, hence its basicity decreases. no such resonance is seen in cyclohexyl amine, and the lone pair is available to abstract protons and it is stronger base than aniline.
Cyclohexylamine is a stronger base than aniline because the nitrogen atom in cyclohexylamine is less hindered by bulky substituents than in aniline. This allows for easier access of the lone pair of electrons on nitrogen in cyclohexylamine, making it more available for proton transfer. Aniline's lone pair is more delocalized into the benzene ring, which reduces its basicity.
Sodium hydroxide is a stronger base compared to ammonia. This is because sodium hydroxide has a higher dissociation constant (pKa) and is more effective at donating hydroxide ions in solution, resulting in a higher pH compared to ammonia.
Aniline is a stronger base than o-nitroaniline because the nitro group in o-nitroaniline is electron-withdrawing and decreases its basicity compared to aniline. In basicity trends for amines and anilines, the presence of electron-withdrawing groups decreases basicity.
Sodium hydroxide is stronger than ammonia because it is a strong base, dissociating completely in water to release hydroxide ions. On the other hand, ammonia is a weak base and only partially dissociates in water. This results in sodium hydroxide having a higher concentration of hydroxide ions, making it more reactive and stronger than ammonia.
aniline is more acidic because in aniline a electron withdrawing benzene is connected.electron withdrawing capacity of benzene is due to its delocalizing pi electrons cloud.due the action of benzene the presence of unshared pair of electron over nitrogen is somehow decreases.which increases its acidic nature. But in case of ammonia there is no electron withdrawing group.so its unshared pair of electron remains undistrubed,which decreases its acidity and increases its basisity
There is no real basis for comparison but nitric acid is a strong acid and ammonia is a weak base.
Aniline is less basic than ammonia because the nitrogen lone pair on aniline is partially delocalized into the benzene ring, making it less available to accept a proton. Ammonia, on the other hand, has a more localized lone pair on nitrogen, which is more readily available for protonation.