Want this question answered?
When copper gets burned, its own identity vanishes and it changes into a black coloured powdery substance. This substance is copper oxide. The reaction is as follows:- 2Cu(s) + O2(g) ------> 2CuO(s)
amphoteric, it reacts with an acid or a base to form a salt and water (a neutralisation reaction) ZnO(s) + 2HCL (aq) = ZnCl2(aq) + H2O(l) ZnO (s) + 2OH- (aq) = ZnO22-(s) + H2O(l)
The copper wire glows red. Once it cools...the copper reacts with the air to produce copper(II) oxide. This is shown by the black tarnish on the copper wire.
Copper(II) oxide is CuO. When binary compounds (compounds composed of only two elements) decompose, they produce their elements. So the unbalanced equation would be: CuO(s) --> Cu(s) + O2(g) Now you have 1 Cu and 1 O on the reactant side and 1 Cu and 2 O on the product side. To balance, first put a coefficient of 2 in front of CuO so each side has 2 O. 2CuO(s) --> Cu(s) + O2(g) This leaves 2 Cu on the reactant side, but only 1 Cu on the product side so now put a coefficient of 2 in front of Cu so each side has 2 Cu. 2CuO(s) --> 2Cu(s) + O2(g) The equation is balanced!
The equation for this reaction is CuO (s) + H2SO4 (aq) -> CuSO4 (aq) + H2O (l).
Zn(s) + CuO(s) → ZnO(s) + Cu(s) Copper metal and Zinc Oxide is formed.
There are two different copper oxide formula's:2Cu + O2 -> 2CuO (black Copper(II) oxide)or4Cu + O2 -> 2Cu2O (red Copper(I) oxide)Copper(II) = Cu2+Oxide = O2-CuO or copper(II) oxide
Copper(s)
CuO(s) + 2HCl(aq) --> CuCl2(aq) + H2O(l) Copper oxide + Hydrochloric Acid --> Copper Chloride + Water
Copper(2)oxide is written as Cu2O.Not that the last alphabet is O for oxygen,not 0 for zero Actually Copper (II) Oxide is written as CuO, because Copper 2 has the charge 2+ and Oxygen has the charge 2-, so they balance each other out evenly. THere is no need for 2 (Cu2)'s.
Copper doesn't react with carbon dioxide at room temperature.
Cu(OH)2 can be regarded as unstable ['copper oxide'-'hydrate'], and as such it easily loses a water (H2O) molecule, eg. when heated:Cu(OH)2(s) --> [CuO.H2O] --> CuO(s) + H2OOnly hydrated copper ions are blue colored.(Compare white CuSO4(s) and blue CuSO4.5H2O(s) )
Here are the equations for the thermal decomposition of copper carbonate (notice that a metal oxide is formed, just as it was with calcium carbonate): Copper carbonate → copper oxide + carbon dioxide CuCO3 → CuO + CO2
When solid cesium oxide is added to water, you get this equation:Cs2O (s) + H2O (l) --> 2 CsOH (aq)
2Cu (s) + O2 (g) -----------------> 2CuO (s)
CuO + H2SO4 ----> CuSO4 + H2O The products are Copper(II) sulphate and water
The brown colored element, copper on heating in air forms copper oxide which in black in color. 2Cu(s) +O2(g) gives rise to 2CuO(s)