It's a difference in mentality; some believe 0 is the begin, and is thus the only logical choice, and some think the opposite.
Yes. We can create an array of zero length in JAVA. Here is an example:class ForFun{int[] nullArray=new int[0];public someMethod(){for(int j=0; j
Primarily to be compatible with C and C++, which was one of the goals of Java when it was being designed (minimize the learning curve for those familiar with C and C++ to increase adoption). Speaking from a lower-level perspective, arrays are accessed by a pointer and an index. If you call the pointer PTR, and the index IDX, you can access an element in the array by using PTR+IDX. In order to avoid wasting memory, IDX may be zero, since PTR is already allocating that memory to the existence of the array. In languages where IDX starts at 1, PTR[0] stores the number of elements in the array, and can't be directly accessed. Java stores the length of the array elsewhere (in the variable "length"), and so it can start its element allocation at zero.
Array subscripts always have a zero-based index. In languages that allow an n-based index, the index is simply offset by n elements, so the compiler subtracts n from the given index to obtain the zero-based index. Arrays are always zero-based because the first element of an array is found zero elements from the start of the array.
Because by the laws of mathematics, you cannot divide anything by zero. So you will have to adjust your code to allow for that fact.
Loops can be used to iterate or walk through an array. For example, suppose you have an array already initialized (we'll call it "array"): int target = -1; for (i=0; i < array.length(); i++){ if (array[i] = target){ //do something } } Here, we will walk through an array (note that arrays are zero indexed) using a loop to make sure we hit each element of the array. In our loop, we start at the head (or first element) and iterate over each element.
Yes. We can create an array of zero length in JAVA. Here is an example:class ForFun{int[] nullArray=new int[0];public someMethod(){for(int j=0; j
Zero.
Primarily to be compatible with C and C++, which was one of the goals of Java when it was being designed (minimize the learning curve for those familiar with C and C++ to increase adoption). Speaking from a lower-level perspective, arrays are accessed by a pointer and an index. If you call the pointer PTR, and the index IDX, you can access an element in the array by using PTR+IDX. In order to avoid wasting memory, IDX may be zero, since PTR is already allocating that memory to the existence of the array. In languages where IDX starts at 1, PTR[0] stores the number of elements in the array, and can't be directly accessed. Java stores the length of the array elsewhere (in the variable "length"), and so it can start its element allocation at zero.
Nothing, zero-terminated char-arrays are used instead of strings.
It's still a liquid but it will have a spherical shape.
Array subscripts always have a zero-based index. In languages that allow an n-based index, the index is simply offset by n elements, so the compiler subtracts n from the given index to obtain the zero-based index. Arrays are always zero-based because the first element of an array is found zero elements from the start of the array.
Because of pointers and that all arrays are really pointers. A pointer something like *pointer can also be written as pointer[0] and *(pointer + 1) can also be written as pointer[1]
0. For many (every) languages, for every type of array, the starting subscript is zero.
Zero. By default they do not implement any interfaces.
no but bar graphs do have to start at zero
Because by the laws of mathematics, you cannot divide anything by zero. So you will have to adjust your code to allow for that fact.
zero, as in zero degrees