The NaOH neutralizes the acetic acid, producing sodium acetate and water. The acetic acid is no longer present to produce an odor.
By the reaction with NaOH and excess Cl2
0.26
0.01 molar
The reaction between ethanoic acid (acetic acid) and sodium hydroxide is a double replacement one. Normally a reaction between an acid (acetic acid in this case) and a base (like NaOH) involves neutralization, which in turn produces water.
An acid and a base cause neutralization.
By the reaction with NaOH and excess Cl2
.26
0.26
0.01 molar
The reaction between ethanoic acid (acetic acid) and sodium hydroxide is a double replacement one. Normally a reaction between an acid (acetic acid in this case) and a base (like NaOH) involves neutralization, which in turn produces water.
An acid and a base cause neutralization.
that is due to acetic acid is a weak acid and sodium hydroxide is a strong base. hence when they are titrated pH increases
Because hydroxide (OH-) is a strong base reacting completely with undissociated acetic acod (CH3COOH) to leave only acetate ions (CH3COO-) and water when completed.
Weak Acid with a Strong Base, e.g. acetic acid with NaOH: Initially the conductance is low due to the feeble ionization of acetic acid. On the addition of base, there is decrease in conductance not only due to the replacement of H+ by Na+ but also suppresses the dissociation of acetic acid due to common ion acetate. But very soon, the conductance increases on adding NaOH as NaOH neutralizes the un-dissociated CH3COOH to CH3COONa which is the strong electrolyte. This increase in conductance continues raise up to the equivalence point. The graph near the equivalence point is curved due the hydrolysis of salt CH3COONa. Beyond the equivalence point, conductance increases more rapidly with the addition of NaOH due to the highly conducting OH− ions
Glacial acetic acid reacts with sodium hydroxide to give sodium acetate and water CH3COOH + NaOH = CH3COONa + H2O
CH3COOH + NaOH = CH3COONa + H2O
CH3COOH+NaOH=CH3COONa+H2O