My lightbulb stayed lit after I removed it all from the copper sulfate solution because electrodes were still working.
Copper sulphate is a blue coloured solution. As soon as you react it with iron, you will notice that the solution is turning into light green which means iron sulphate solution is forming. Iron being more reactive than copper displaces copper from its soluion.
The aqueous solution of ferrous sulfate, FeSO4, is light green on heating. It changes to yellow then brown due to formation of ferric sulfate.
It will shine, but dimly.
A displacement reaction takes place. Iron being a more reactive element than copper displaces copper from its compound. Ferrous Sulphate which is green in color and copper a reddish brown element are formed. So, blue color of copper sulphate fades away and the solution becomes light green. Copper is deposited on the grayish iron filings.
orange-red
When an iron nail is dipped in the copper sulfate solution then iron displaces copper from the copper sulfate because iron is more reactive than copper.
Copper sulphate is a blue coloured solution. As soon as you react it with iron, you will notice that the solution is turning into light green which means iron sulphate solution is forming. Iron being more reactive than copper displaces copper from its soluion.
nothing will happen as i have done this experiment. I think it is because iron is more reactive than copper, so the copper can't take away the sulphate. but if you added the iron to a copper sulphate solution the product would be iron sulphate this reaction is called displacment. David corrected by hari
The aqueous solution of ferrous sulfate, FeSO4, is light green on heating. It changes to yellow then brown due to formation of ferric sulfate.
It will shine, but dimly.
The result is a clear blue liquid that reflectes light off it. I don't much about it and I'm looking on the internet to get a better understanding of it. But, it was during a school experiment and this is what me and my partner discovered.
A displacement reaction takes place. Iron being a more reactive element than copper displaces copper from its compound. Ferrous Sulphate which is green in color and copper a reddish brown element are formed. So, blue color of copper sulphate fades away and the solution becomes light green. Copper is deposited on the grayish iron filings.
Depends on the length the light traveled through the solution and the solution concentration. molar absorption = absorbance/(length x concentration) length is typically in cm and concentration is typically in mol/L
iron(Fe) being more reactive than Copper(Cu) displaces Cu from copper sulphate (CuSO4). Thus, the following equation is derived:Fe + CuSO4 -----> FeSO4 + CuOBSERVATIONS-1. reddish-brown deposit on the surface of nail2. surface of the nail is found corroded3. the blue solution turns light green
Benedict's reagent starts off light blue. (from the copper(II) sulfate) As glucose levels in the solution rise the color will proceed as follows: green, yellow, orange, red and brick red The brown/red color comes from the formation of copper(I) oxide an insoluble precipitate.
orange-red
Copper sulphate is a blue coloured solution. As soon as you react it with iron, you will notice that the solution is turning into light green which means iron sulphate solution is forming. Iron being more reactive than copper displaces copper from its soluion.