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Why do the current readings differ for increasing and decreasing values of the incandescent lamp wattages?
Wiki User
∙ 12y ago
While Voltage and Resistance typically remain constant in incandescent lamps: P (Power in Watts) = I (Current in Amperes) times E (Electrostatic energy in Volts [AC and DC]).
P=I*E - when P (Watts) goes up so does I (Amps).
Wiki User
∙ 12y ago
Wiki User
∙ 12y agoYou are incorrect to describe voltage and current as being 'characteristics' of incandescent lamps, or any other type of load come to that. Voltage is a characteristic the supply, not by the lamp, while the load current is determined by the power of the lamp which, again, is determined by the supply voltage.
A lamp (in fact any type of load) is rated according to the voltage at which it is designed to operate, together with the power it will develop at that voltage. For example, '60 W at 230 V'.
A lamp's rated power will only be achieved at its rated voltage. If a voltage below its rated voltage is applied to the lamp, then its resulting power will fall significantly -one of the reasons why utility companies are required to maintain their supply voltages between mandatory limits.
Wiki User
∙ 12y agoIt is Ohm's law in its truest form. Current is directionally proportional to the voltage and inversely proportional to the resistance in the circuit. As the voltage goes up so does the current because the resistance remains constant. If different lamps had different resistances then the current would be inverse, meaning the higher the resistance became the lower the current would become. The lower the resistance in the bulb became the higher the current would become. I = E/R, R = E/I.
Wiki User
∙ 6y agoAs the voltage changes the current changes too to deliver the rated power
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