If two ideal sources of unequal voltage are connected in parallel the higher voltage will provide a majority of the current (a two percent difference in voltage would provide an additional 5% of the current) and (in the case of batteries) the larger would provide charging current, quickly draining it.
While the dynamic voltage restorer is good there are some disadvantages. These include its size and shape, the possibility of interference, and it is fixed and cannot be adjusted.
a stand alone machine is a machine which cannot communicate with other computers, i.e is not connected to any sort of network (this includes a home or corporate network, and the internet)
blocking refers to when an input terminal cannot be connected to an output terminal because there is no path available between them i.e. all possible intermediate switches are occupied
This is important when meter cannot display negative values, e.g. it is analogous meter with scale. Most digital meters can display negative values. P.S. I am amateur in elecrtonics.
Watts = current x volts, so you have to multiply Kw value by 1000 to get watts, then divide by the applied voltage. examples. 2Kw kettle (U.S) current = 2 x1000 divided by 120, or 16.7 amps 2Kw kettle (UK) current = 2 x1000 divided by 240 or 8.35 amps 100 watt car amplifier current = 100 divided by 12 volts = 8.5amps
You cannot connect transformers of different voltage in parallel. This is because circulating currents will be set up between the two transformers that may exceed their rated currents.
Yes of course.. u just need some connecting wires to connect them in parallel
The current, if connected to a voltage source that can supply the needed current to (R1+R2) R3, will be unchanged. If the source cannot supply the needed current, the terminal voltage will decrease, which will change the current flowing through R1 and R2.
It cannot. A trapezium is a quadrilateral that has one pair of parallel but unequal sides and another pair of non-parallel sides. A parallelogram has two pairs of parallel and equal sides.
Appliances have to be connected in a parallel circuit to keep the voltages the same for each appliance (they were designed to work with one voltage) , this does not mean that the power output will be the same, the more appliances there are the more current (i.e. power) will be needed to for the appliances and this can go on until the grid cannot supply any more (and you blow a fuse)
A voltmeter needs to be connected in parallel with the part of the circuit you are checking. It records a change in voltage, and has a high internal resistance, so it cannot be connected in series unless you want to screw up the circuit. Set the meter to AC or DC volts and place the wires of the terminal across the resistor, switch, or any other potentially resistive part of the circuit.
Yes. this is commonly done. However, performance is better and costs lower if you use the proper diode for production devices. Absolutely NOT. For the same reason that capacitor cannot be added in series to withstand higher voltage. Not all components are made equally Supposed that you have two diodes rated at 100v add them in series makes 200v not quite if one leaks more then the other unequal voltage will results blowing them up. There is a simple solution add a parallel high resistor across each component to equalize the voltage then YES it is possible to add them in series
That depends on several factors that aren't specified in the question: -- whether the resistors are connected to each other -- whether they're connected in series or in parallel -- the voltage applied across the ends of the circuit While these two resistors are in their plastic packages hanging on the wall at Radio Shack, the total current flowing through both of them is zero.
A rectangle cannot be considered a rhombus because, even though both have two pairs of parallel sides, the sides of a rhombus are congruent. A rectangle's sides are unequal.
Theoretically this cannot happen because a voltage source isn't practically available. If you managed to find near perfect voltage sources of differing voltages and put them in parallel then you'd get some massive currents flowing. Why? You have two sources each wanting there own voltage to exist across itself, by putting them in parallel they will practically settle at a voltage somewhere between the two. This settling voltage will be determined by the internal resistances of each source. If R1=internal resistance of the 4.5V source and R2=internal resistance of the 5V source. Current flow=Voltage difference / resistance. So current flow=0.5/(R1+R2) Settling Voltage = 4.5 + (current *R1) = 4.5+0.5*(R1/(R1+R2)) So if R1=0.001 and R2=0.002 Ohms Current = .5/(.003) = 167 Amps Voltage = 4.5 + .5*(.001/.003) = 4.67V. This explains why you shouldn't put power batteries in parallel, there is a risk of massive currents to flow. Andrew
A current cannot exist without voltage but voltage can exist without current.Simple example is battery. A battery has votlage even though it is not connected elsewhere.
You cannot 'verify' Ohm's Law with a series or parallel circuit. The only way of verifying Ohm's Law is to plot a graph of current against voltage for variations in voltage. If the resulting graph is a straight line, then you have verified Ohm's Law for the load you have used.