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If air resistance can be ignored, then both objects are moving under the same force: gravity. The force is directly proportional to the masses of the objects.

Thus if the masses are Mp and Mq

then Gp = k*Mp and Gq = k*Mq where Gp and Gq are the forces acting on the two bodies.


The acceleration of the two objects is inversely proportional to their masses. [F = m*a => a = F/M]

So acc(p) = Gp/Mp = (k*Mp)/Mp = k

and acc(q) = Gq/Mq = (k*Mq)/Mq = k

That is, the acceleration of the two bodies is the same. Consequently, because they start from rest from the same height, they will hit the ground at the same time.

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7y ago
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7y ago

This assumes that air resistance can be neglected.The reason is that both are accelerated at the same rate by Earth's gravitational field - about 9.8 meters per second squared.

Consider that an object that has (for example) 10 times more mass, and will therefore be attracted 10 times as strongly by Earth, also has 10 times as much inertia.

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6y ago

Gravitational acceleration is identical for both.

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Q: Why do two objects of different mass and dropped from the same height hit the ground at the same time?
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