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There is no problem using a generator to run more inductive load so long as the generator capacity can supply the needed power to the inductive loads. The inductive loads should not be switched on at the same time but there should be a little delay before another load is switched ON as inductive loads draw more power at start ON. The power factor of the inductive loads also affect the generator, hence for safe operation a power factor that is approaching 1 is desirable. Ogu Reginald Ekene
To interrupt the current requires a more-expensive circuit-breaker. An isolator is used to isolate a section of power line after the current has been stopped.
Voltage leads current or, more specifically current lags voltage, in an inductive circuit. This is because an inductor resists a change in current.
For a 3 phase motor, the voltage is 415. Being an inductive load the power factor is commonly .85 The constant for 3 phase circuit is 1.732 You need to run the motor on no load and you use clamp meter to take the no load current. In considering the fact that on no load the measured current should not be more than 0.5 of the rated. Assuming , under normal condition the no load current is 10 amps. Then the load current will be 20 amps. Then from above and in using the formula P=I*V*p.f*1.732 Therefore P= 20*415*0.85*1.732. P=12.3 kw Thank you. Bankole 2348035447224
It depends on the nature of the circuit. In a purely-resistive circuit, the current would rise immediately because resistance merely limits its value, it doesn't oppose any change in current. But in a resistive-inductive circuit, for example, the inductive component opposes any change in current, so the current will rise more gradually.
Voltage and current will be in phase for a purely resistive load. As a load becomes more inductive or capacitive, the phase angle between voltage and current will increase.
There is no problem using a generator to run more inductive load so long as the generator capacity can supply the needed power to the inductive loads. The inductive loads should not be switched on at the same time but there should be a little delay before another load is switched ON as inductive loads draw more power at start ON. The power factor of the inductive loads also affect the generator, hence for safe operation a power factor that is approaching 1 is desirable. Ogu Reginald Ekene
To interrupt the current requires a more-expensive circuit-breaker. An isolator is used to isolate a section of power line after the current has been stopped.
it requires more energy to pull because the load is heavier than the effort.
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
Yes because the transformer heating (power losses) depend on the load current and the load voltage. It can be assumed that the voltage stays more or less constant, therefore the iron loss is also constant. The copper loss depends on the square of the load current. So it is the VA of the load that determines the power loss and any heating.
Most of the time a load is inductive. A capacitor counters this effect by making the voltage and current more in phase (so there is greater real power, P=VI*cos(angle)). If the load were to be capacitive in nature, then an inductor would be used in parallel to the load to counter the effects of the capacitors.
Inductive load where current lags voltage to keep the power factor low thus increasing the consumption of more electrical units of supply provider. This is since an inductive load draws reactive power as well with active power. Reactive component is watt less power drawn from the source. We use only active part of the source. But pays from active+reactive parts. This low power factor also effects the other systems in the circuit virtually making the cables under sized by heating them
it increases because increasing load means more output power, more output power means more current
The starting current of any electrical equipment which is 6 times more than that of the full load current. ex: full load current = 5 A the starting current will be 5*6 = 30 A.
due to high reluctance air gap magnetisation current is very high as a result no load current is more
Voltage leads current or, more specifically current lags voltage, in an inductive circuit. This is because an inductor resists a change in current.