This is because the elements in the first period only use their s orbitals, youll notice that Hydrogen is 1S and exists as the diatomic H2 and that Helium has the configuration 2S and exists as free Helium. The reason for this is that any S orbital can only hold two electrons, the octet rule applies when there are S and P orbitals present which can hold up to 8 electrons( 2 from the S orbital and 6 from the D orbital).
The octet rule only applies to elements that are heavy enough to have reached the second shell of electrons. In the first shell, the octet rule does not apply because the first shell is completed with only two electrons, not eight. So no, the octet rule does not apply to beryllium hydride.
1. Less than the octet Elements B and Be 2. More than the octet Elements from Period 3 and beyond. Since these elements have d orbitals (n=3, therefore they contain an s,p and d), the d orbital can accommodate extra electrons during bonding. 3. Free radicals Molecules with at least one unpaired electron.
I know Hydrogen and Helium for sure, not sure about the other elements. The noble gases.
The octet rule does not apply to transition and inner transition metals and to the first for or five elements in the periodic table.
There is ClO2 and ClO2^-. For the chlorite anion (ClO2^-) the Cl will have 10 electrons and will violate the octet rule. For ClO2, all elements will have 8 electrons.
yes!
The octet rule is the tendency of many chemical elements to have eight electrons in the valence shell.
The elements can be described by dot structure. Metals combine with other elements to make its octet complete.
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
octet rule
The octet rule only applies to elements that are heavy enough to have reached the second shell of electrons. In the first shell, the octet rule does not apply because the first shell is completed with only two electrons, not eight. So no, the octet rule does not apply to beryllium hydride.
1. Less than the octet Elements B and Be 2. More than the octet Elements from Period 3 and beyond. Since these elements have d orbitals (n=3, therefore they contain an s,p and d), the d orbital can accommodate extra electrons during bonding. 3. Free radicals Molecules with at least one unpaired electron.
The octet rule is the tendency of many chemical elements to have eight electrons in the valence shell.
I know Hydrogen and Helium for sure, not sure about the other elements. The noble gases.
The octet rule does not apply to transition and inner transition metals and to the first for or five elements in the periodic table.
Some elements that are known to violate the octet rule are: Hydrogen, Helium and Lithium (two electrons) Aluminum and Boron (less than octet but will form an octet if possible), Period 3 elements with p orbitals (more than an octet using empty d orbitals), noble gas compounds (more than an octet), and elements like nitrogen with an odd number of electrons (form free radicals when octets are not possible).
The octet rule also known as the rule of eight