The elements can be described by dot structure. Metals combine with other elements to make its octet complete.
Hydrogen does not obey the octet rule. Boron does not always obey the octet rule and in fact forms Lewis acids such as BF3 which only has 6 electrons.
No chlorine oxides will obey the octet rule.
no it does not follow octet rule
H and I SCl4 ICl3 SeCI4 F2CCF2
Chlorine Cl : it can have a higher valence (ClO2, HClO3) than predicted by the octet rule. Hydrogen H and oxygen O cannot escape the octet rule.
Hydrogen does not obey the octet rule. Boron does not always obey the octet rule and in fact forms Lewis acids such as BF3 which only has 6 electrons.
No chlorine oxides will obey the octet rule.
No, Transition metals do not obey the octet rule in simple compounds , Am is an 'f' block transition metal.
no it does not follow octet rule
BF3 and other Lewis acids. Also BrF5 and other inter-halogen compounds.
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
most metals do not follow the octet rule. when an atom has access to the D orbitals it usually follows the 18-electron rule (transition metals). non transition or F block elements usually contain a d orbital (when present) that is below the s and p orbitals in energy and do not usually use D electrons in bonding.
BCl3 is the formula for Boron Chloride. As a matter of interest it does not obey the octet rule. It is also called a Lewis Acid.
No, SF6 doesn't. If you draw out the Lewis structure, all 6 fluorine atoms have to connect to the sulfur.
The octet rule does not apply to transition metals.
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
Yes