Hydrogen does not obey the octet rule. Boron does not always obey the octet rule and in fact forms Lewis acids such as BF3 which only has 6 electrons.
H/ Br
Chlorine Cl : it can have a higher valence (ClO2, HClO3) than predicted by the octet rule. Hydrogen H and oxygen O cannot escape the octet rule.
No chlorine oxides will obey the octet rule.
no it does not follow octet rule
H and I SCl4 ICl3 SeCI4 F2CCF2
The elements can be described by dot structure. Metals combine with other elements to make its octet complete.
H and l
Chlorine Cl : it can have a higher valence (ClO2, HClO3) than predicted by the octet rule. Hydrogen H and oxygen O cannot escape the octet rule.
No chlorine oxides will obey the octet rule.
The oxygen atoms in the ion do obey the octet rule. The phosphorus atom has more than eight electrons in its valence shell. It is because of the existence of vacant 3d orbitals.
Yes. Both O-F bonds are single covalent, so all three atoms can claim 8 electrons.
The bolded statements are true:1. The octet rule can be violated. 2. Atoms are most stable when their atomic number is divisible by 8.3. All free atoms contribute eight valence electrons to form molecules.4. Only the oxygen atom can have an expandable octet.5. In order to obey the octet rule, some atoms have to share more than one pair of electrons.
No. Some molecules, such as boron triflouride (BF3) and phosphorus pendachloride (PCl5) are octect violators.
No, SF6 doesn't. If you draw out the Lewis structure, all 6 fluorine atoms have to connect to the sulfur.
no it does not follow octet rule
Covalent.
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
because it does