Because emf is the very source of voltage, either chemical or inductive, an can be meassured at open circuit only so, internal resistance of the supplier is not affecting it.
One way to determine current is to measure it, with an ammeter. Another way is to calculate it using Ohm's law: current = voltage / resistance.
Voltage drop is resultant of IR ie current and the line resistance, not dependent on impressed emf
Internal resistance
The higher the resistance the lower the current flow. It restricts the flow of electrical current. The resistance will not depend upon the current. The current flow will depend on the resistance.
I don't think you can do that, with the information provided.
A: The EMF and total resistance
You can measure the emf of a cell by using a voltmeter, as this draws current from a cell. You can use the voltage, the emf, and the load resistance to determine the internal resistance of the cell.
One way to determine current is to measure it, with an ammeter. Another way is to calculate it using Ohm's law: current = voltage / resistance.
magnet produce emf it maintain the resistance as same
Voltage drop is resultant of IR ie current and the line resistance, not dependent on impressed emf
The current flow in an electrical circuit depends on the applied electromotive force (EMF, measured in volts), and the total resistance along the entire circuit. Rising EMF or dropping resistance cause increased current flow
No. But the current through it does.
Yes, that is what it is called.
Internal resistance
The higher the resistance the lower the current flow. It restricts the flow of electrical current. The resistance will not depend upon the current. The current flow will depend on the resistance.
You don't. If you know how many Amperes in an electrical circuit and also what the total resistance in the circuit is, then EMF (Volts) = current (Amps) x resistance (in Ohms). EMF stands for Electromotive Force, and its unit of measure is the Volt.
it doesn't develop emf ..........