Want this question answered?
That has no effect on the resistance. The current doubles also.
Resistance is a concept used for DC. the current through a resistance is in phase with the applied voltage Reactance is used for AC the current through a inductive reactance lags the applied voltage by 90 degrees. the current through capacitive reactance leads the applied voltage by 90 degrees. the net reactance is the difference between inductive and capacitive reactance
-- Apply a small, known voltage between the terminals of the device. -- Measure the current through the device with the voltage applied. -- Calculate the resistance of the device. It's (voltage) divided by (current).
In a conventional current, the electric field points the way decreasing electric potential goes. The current from the positive terminal is at a higher potential toward the negative terminal, which means the current is in the direction of decreasing potential.
No, you is false. Increasing current does it, but the number of turns in the coilalso must increase if you want to increase the magnetic field that way.
Ohm's law. Current is directly proportional to the applied emf and inversely proportional to the resistance in the circuit.
As Ohm's law states; Current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit.
Increase current by either increasing the voltage or decreasing the resistance.
Increasing resistance decreases current.
Increasing resistance decreases current.
Ohm's Law states that the current (I) flowing in a circuit is directly proportional to the applied voltage (E) and inversely proportional to the circuit's resistance (R).I = E/RAnother way of stating Ohm's Law is that the applied voltage (E) is directly proportional to both the current (I) and the resistance (R).E = IxR.So, if the voltage (E) is increasing, then either:if you know the resistance (R) is staying constant then the current (I) must be increasing - which you would see because you are monitoring it! or, if the current (which you are monitoring) is actually staying constant, then, for the voltage to be able to increase:the circuit's resistance must be increasing orthe increasing voltage could be caused by a combination of both increasing current and increasing resistance!
Ohm's law: Voltage = Amperes times Resistance. This means that increasing voltage while keeping resistance the same must result in an increase of current.
An ammeter has a finite resistance which is inserted in series with the rest of the circuit, increasing the total resistance and decreasing the current. A good ammeter has a very low resistance, so it shouldn't affect the circuit noticeably.
A: Decreasing the current and/or the resistance
.The magnitude of the voltage and current of both the armature and shunt field coil. To decrease the speed when the load is increasing then increase the shunt field current while decreasing the armature voltage or current. To increase the speed while the load is increasing then increase the armature current while decreasing the shunt field current. The decreasing and increasing of these currents and voltages can be done by connecting a variable resistor in series or parallel with each of the armature and/or shunt field coil.
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
at the time of decreasing lamp voltage as the temperature is already high the gas in the lamp is already in ionized state leading to different resistance ,but when increasing voltage the gas is not in ionized state it ready to ionize ,so there is slightly variation in resistance . :)