inductor was invented by scientist lenz so it is denoted by l..
letter symbol is L
The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.
t = L/R
Yes, it possible to heat a coil using dc power supply. An inductor resists a change in current, proportional to voltage and inversely proportional to inductance. The equation of an inductor is di/dt = v/L An ideal inductor, if connected to an ideal DC supply, with ideal conductors, would ramp up current in a linear fashion without limit, eventually reaching infinity amperes after infinite time. Since no inductor is ideal, nor is any DC supply, nor is any conductor, the current would reach a maximum based on the capacity of the DC supply and the DC resistance of the inductor and conductors. Since the DC resistance of the inductor is also not zero, this means, by Ohm's law, that the inductor must dissipate some power. That will cause the inductor to heat up.
Since the equation of an inductor is ... di/dt = v/L ... then increasing the current in the RL network would cause a back-emf in the inductor that would initially seem to oppose the series current. More correctly, the question should ask "what if the voltage were increased?"; and the answer is that the rate of change of current in the inductor would increase, but the current would not initially change. This is the case for a series RL. For a parallel RL, increasing the current would initially show up as an increase the the current through the R, increasing voltage in the L, with the same effect as noted above.
letter symbol is L
L is the symbol for inductance. An inductor is a passive two-terminal electrical component which resists changes in electric current passing through it.
The inductor symbol resembles a coil of wire of 3 to 5 turns.
Since we know that inductance of an inductor depends on the length of inductor by the formula L=muAN*N/l, where l is the length of inductor. So by varying the length of inductor we say that inductance of inductor varies.
The term 'inductance' was coined by Oliver Heaviside in February 1886.[1] It is customary to use the symbol L for inductance, possibly in honour of the physicist Heinrich Lenz.
Inductor is a nonlinear device. since v=L di/dt.
You surely do mean inductor, not capacitor. The length is not enough to determine the number of windings for an inductor. Inductance is bound with following parameters by equation: L = (pi/4) * mi * (N * d)^2 / l, where: L - inductance mi - permeability of inductor core N - number of windings d - diameter of inductor l - length of inductor Using those data, you can transform the equation to: N = sqrt(2*L*l/(mi*pi))/d
It doesn't. the impedance of the inductor will, following the rule j*w*l, where l is inductance, w is frequency in radians and j is the imaginary number designating this a reactance, not resistance.
The resulting maximum current is limited by the resistance of the inductor. As the current increases from zero to that maximum value, its expanding magnetic field induces a voltage into the inductor which opposes the rise in that current. So, instead of reaching its maximum value instantaneously, it takes some time -determined by the equation:time to maximum current = 5 L / R (seconds)where L = inductance of inductor in henrys, and R = resistance of inductor in ohms.
Yes, with some difficulty. You can think of an inductor as a kind of "AC resistor"in a way. The higher the frequency of the AC, the more difficulty it has passingthrough the inductor.If you apply AC voltage across an inductor, whereV = voltage of the ACf = frequency of the ACL = inductance of the inductor,then the AC current through the inductor isI = V/2 pi f L
Energy stored in the inductance 'L' through which the current 'I' flows is [ 1/2 L I2 ].
Because an inductor resists a change in current. The equation of an inductor is ...di/dt = V/L... meaning that the rate of change of current is proportional to voltage and inversely proportional to inductance. Solve the differential equation in a sinusoidal forcing function and you get inductive reactance being ...XL = 2 pi f L