Iron loss it includes the core loss is partically the same at all loads and copper loss the value of cu loss is found from short circuit test
It doesn't, really. The power loss in transformers is broken down into copper loss and iron loss. The copper loss comes from the resistance of the windings in the transformer and depends on the load current, while the iron loss in the magnetic core depends on the magnetic flux density and is constant if the supply voltage is constant.
since the iron loss depends only on the volage and frequency,the supply volage is 230v ac.Hence iron loss is always constant
because of its losses i.e iron and copper losses. since iron loss depends on voltage (v)and copper loss depends on current(i).
Iron losses are due to energization of the transformer; they do not depend on the loading of the transformer. They will vary depending on the voltage applied to the transformer. The best model of this is a parallel connection to the ideal transformer winding.
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
Maximum efficiency of a power transformer occurs when copper loss equals to iron losses. Decrease in current does not result in increase in efficiency unless the copper loss was more than iron loss and the decreased current made the copper loss is reduced and became equal to iron loss at some point.
The transformer will have the maximum efficiency.
because iron loss is depends on frequency and it is constant through out the operation ...irrespective from load
It doesn't, really. The power loss in transformers is broken down into copper loss and iron loss. The copper loss comes from the resistance of the windings in the transformer and depends on the load current, while the iron loss in the magnetic core depends on the magnetic flux density and is constant if the supply voltage is constant.
since the iron loss depends only on the volage and frequency,the supply volage is 230v ac.Hence iron loss is always constant
The maximum efficiency condition in distribution transformer is said to be occurred when iron loss = copper loss
because of its losses i.e iron and copper losses. since iron loss depends on voltage (v)and copper loss depends on current(i).
Copper losses are directly related to loading of the transformer. Iron (core) losses are a result of magnetizing of the core of the transformer, and are relatively constant from no load to full load. With this in mind, it should be clear that the above statement is false. Maximum efficiency results with low core losses, and low copper losses. Copper losses cannot be helped, so it is important to minimize core losses to increase the efficiency of a transformer.AnswerYes, it is perfectly correct -well, with the proviso that transformers normally operate somewhat below full load and, so, are designed to achieve maximum efficiency somewhat below full load. A transformer's maximum efficiency does indeed occur when the copper losses and iron losses are equal. Unfortunately, the mathematical proof of this is too complicated to reproduce here, I suggest that you check out any reputable electrical engineering textbook.
Basically two types: 1. Copper losses:- when the transformer is loaded, current flows in primary and secondary winding, there is loss of electrical energy due to the resistance of the primary winding, and secondary winding and they are called variable losses. These losses depend upon the loading conditions of the transformers. Therefore, these losses are also called as variable losses. 2. Iron losses or core losses:-The losses that occur in the core are known as core losses or iron losses. Two types of iron losses are: > eddy current loss > Hysteresis loss.
Yes because the transformer heating (power losses) depend on the load current and the load voltage. It can be assumed that the voltage stays more or less constant, therefore the iron loss is also constant. The copper loss depends on the square of the load current. So it is the VA of the load that determines the power loss and any heating.
It is the number of turns of copper wire on one side of an iron transformer core to the number of turns on the opposite side of the same iron transformer core. eg. 100 turns on the primary to 25 turns on the secondary is the ratio of 4:1
Iron losses are due to energization of the transformer; they do not depend on the loading of the transformer. They will vary depending on the voltage applied to the transformer. The best model of this is a parallel connection to the ideal transformer winding.