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Iron loss it includes the core loss is partically the same at all loads and copper loss the value of cu loss is found from short circuit test

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Q: Why iron loss is constant but copper loss is variable in a transformer?
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Why the efficiency of a power transformer increases with a decrease in Load at constant PF?

Maximum efficiency of a power transformer occurs when copper loss equals to iron losses. Decrease in current does not result in increase in efficiency unless the copper loss was more than iron loss and the decreased current made the copper loss is reduced and became equal to iron loss at some point.


What will happen if iron losses and copper losses are equal for any transformer?

The transformer will have the maximum efficiency.


Why are iron losses constant at all loads in a transformer?

because iron loss is depends on frequency and it is constant through out the operation ...irrespective from load


How does Lenz's Law explain power loss in transformers?

It doesn't, really. The power loss in transformers is broken down into copper loss and iron loss. The copper loss comes from the resistance of the windings in the transformer and depends on the load current, while the iron loss in the magnetic core depends on the magnetic flux density and is constant if the supply voltage is constant.


Why the iron losses in a transformer is constant at all load prove that?

since the iron loss depends only on the volage and frequency,the supply volage is 230v ac.Hence iron loss is always constant


What is maximum efficiency condition in distribution transformer?

The maximum efficiency condition in distribution transformer is said to be occurred when iron loss = copper loss


Why transformer power expressed in KVA?

because of its losses i.e iron and copper losses. since iron loss depends on voltage (v)and copper loss depends on current(i).


Is this statement true or false the maximuim efficiency of transformer is occured when iron losses is equal to full load copper losses?

Copper losses are directly related to loading of the transformer. Iron (core) losses are a result of magnetizing of the core of the transformer, and are relatively constant from no load to full load. With this in mind, it should be clear that the above statement is false. Maximum efficiency results with low core losses, and low copper losses. Copper losses cannot be helped, so it is important to minimize core losses to increase the efficiency of a transformer.AnswerYes, it is perfectly correct -well, with the proviso that transformers normally operate somewhat below full load and, so, are designed to achieve maximum efficiency somewhat below full load. A transformer's maximum efficiency does indeed occur when the copper losses and iron losses are equal. Unfortunately, the mathematical proof of this is too complicated to reproduce here, I suggest that you check out any reputable electrical engineering textbook.


How many types of losses in transformer?

Basically two types: 1. Copper losses:- when the transformer is loaded, current flows in primary and secondary winding, there is loss of electrical energy due to the resistance of the primary winding, and secondary winding and they are called variable losses. These losses depend upon the loading conditions of the transformers. Therefore, these losses are also called as variable losses. 2. Iron losses or core losses:-The losses that occur in the core are known as core losses or iron losses. Two types of iron losses are: > eddy current loss > Hysteresis loss.


Will transformer heating be approximately the same for resistie inductive or capacitive loads of same VA rating?

Yes because the transformer heating (power losses) depend on the load current and the load voltage. It can be assumed that the voltage stays more or less constant, therefore the iron loss is also constant. The copper loss depends on the square of the load current. So it is the VA of the load that determines the power loss and any heating.


What transformation ratio?

It is the number of turns of copper wire on one side of an iron transformer core to the number of turns on the opposite side of the same iron transformer core. eg. 100 turns on the primary to 25 turns on the secondary is the ratio of 4:1


Why are iron losses considered as constant losses in transformer?

Iron losses are due to energization of the transformer; they do not depend on the loading of the transformer. They will vary depending on the voltage applied to the transformer. The best model of this is a parallel connection to the ideal transformer winding.