AlBr3 is the product thus:
2 Al + 3 Br2 ------> 2 AlBr3
Aluminum has the anion charge of 3+ and a bromine atom has just 1+ thus you need 3 bromine atoms in order to make the product and end up with a non-charged molecule. Unfortunately bromine comes in its diatomic (two of the same atom) in this equation thus you can't have 1.5 of those molecules. If you multiply in such a way, in this case by two, to make everything whole numbers you have your equation.
2Al(s) + 3Br2(l) --> 2AlBr3(s)
1AlBr3 +3K3KBr+1Al
Your unbalanced equation is _Al + _Cr2O3 ----> _Cr + _Al2O3. Multiply aluminum (Al) and chromium (Cr) ratio by 2, so each side has the same amount of each element. As a result, the equation 2Al + Cr2O3 -----> 2Cr + Al2O3 is balanced. This is a single replacement reaction.
The chemical equation is:2 Al(OH)3 = Al2O3 + 3 H2O
The reaction is:Fe2O3 + 2 Al = 2 Fe + Al2O3
you take the mass of Al plus three Br. (27.0) + 3(80.0) the answer is 267.
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
The balanced equation is 3 Fe3O4 + 8 Al -> 4 Al2O3 + 9 Fe. Therefore, the coefficient of Fe is 9.
the answer is 2 apex
The balanced equation is Al(OH)3 + 3HCl ==> 3H2O + AlCl3
sorry i dont know who Al is
Three (3) Here is the equation Al^3+ + 3Br^- = AlBr3
The unbalanced equation: Al + NaNO3 Becomes the balanced equation: Al + 3NaNO3 --> Al(NO3)3 + 3Na for Single Reaplacement.
The balanced chemical equation for the reaction between Al and O2 is: 4Al + 3O2 -> 2Al2O3 Therefore, the coefficient needed for Al to balance the equation is 4.
Aluminium + Oxygen = Aluminium Oxide 2 Al + O2 = 2AlO2
2
This depends on the reaction; aluminium is trivalent Al(3+).
This depends on the reaction; aluminium is trivalent Al(3+).
The balanced equation for aluminum reacting with sulfuric acid is 2Al + 3H2SO4 -> Al2(SO4)3 + 3H2.