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AlBr3 is the product thus:

2 Al + 3 Br2 ------> 2 AlBr3

Aluminum has the anion charge of 3+ and a bromine atom has just 1+ thus you need 3 bromine atoms in order to make the product and end up with a non-charged molecule. Unfortunately bromine comes in its diatomic (two of the same atom) in this equation thus you can't have 1.5 of those molecules. If you multiply in such a way, in this case by two, to make everything whole numbers you have your equation.

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14y ago
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13y ago

2Al(s) + 3Br2(l) --> 2AlBr3(s)

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11y ago

1AlBr3 +3K3KBr+1Al

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Q: Why is a balanced equation for Al plus Br-- and gt AlBr3?
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