Because the impedance of the inductor and capacitor is not a real resistance / has an imaginary value that causes voltage and current to be out of phase.
An inductor's impedance is equivalent to j*w*L (j = i = imaginary number, w = frequency in radians, L = inductance), while a capacitor's impedance is 1/ (j*w*C).
The 'j' causes the phase shift.
Voltage and current are out of phase when the load is reactive, as opposed to purely resistive. This is caused by capacitance (capacitive reactance) and/or inductance (inductive reactance). Basically, capacitive reactance resists a change in voltage, and inductive reactance resists a change in current. This results in a phase shift of current relative to voltage, plus or leading for capacitive, minus or lagging for inductance.
In three phase: I = (three phase VA) / (sqrt(3) x (phase to phase voltage)) for single phase: I = (single phase VA) / ((phase to neutral voltage)) keep in mine three phase VA = 3 x (single phase VA), and phase to phase voltage = 1.732 x (phase to neutral voltage) Therefore the single phase and three phase currents are the same (ie, the three phase currents are the same in all three phases, or balanced). But don't get available current and available power confused (KVA is not the same as KW).
It will depend on input & output voltage, if voltage is same current will remain same
In a capacitor, the current LEADS the voltage by 90 degrees, or to put it the other way, the voltage LAGS the current by 90 degrees. This is because the current in a capacitor depends on the RATE OF CHANGE in voltage across it, and the greatest rate of change is when the voltage is passing through zero (the sine-wave is at its steepest). So current will peak when the voltage is zero, and will be zero when the rate of change of voltage is zero - at the peak of the voltage waveform, when the waveform has stopped rising, and is about to start falling towards zero.
Sum the current and multiply by the line to ground voltage. Never use the phase to phase voltage unless you're dealiing with a dedicated load using all three phases like a 3 phase motor.
Phase to Phase voltageCorrection to the above answer:There is no such thing as a 'phase-to-phase' or 'phase-to-ground' voltage. The correct terms are 'line-to-line' (or 'line voltage') and 'line-to-ground' (or 'phase voltage'). Transmission-line voltages are line-to-line (or 'line') voltages.
The current is the same in the three live wires. The voltage can be described as the line voltage (phase to neutral) or the phase voltage (phase to phase) which is larger by a factor of sqrt(3). So a line voltage of 230 v corresponds to a phase voltage of 400 v.
The phase angle between voltage and current in a purely resistive circuit is zero. Voltage and current are in phase with each other.
a. the current and voltage in phase
Balanced Star (Wye) Connected Systems:Line Voltage = 1.732 x Phase VoltageLine Current = Phase CurrentBalanced Delta Connected Systems:Line Voltage = Phase VoltageLine Current = 1.732 x Phase Current
Assume you are saying that the current and voltage are in phase and you want to know how power is affected. When Voltage and Current are in phase the Power Factor is 1 and you have maximum power being applied. When Voltage and Current are not in phase, Power Factor decreases from 1 toward zero.
Voltage and current will be in phase for a purely resistive load. As a load becomes more inductive or capacitive, the phase angle between voltage and current will increase.
1 & 3
Power factor is the cosine of the phase angle between voltage and current. In a resistive load, current is in phase, i.e. with a phase angle of 0 degrees, with respect to voltage. Cosine (0) is 1.
The power factor is a measure of the phase difference. If they are exactly in phase the PF = 1. If they are 180 degrees out of phase PF = 0.
Yes, but only for balanced loads (current in all three phases the same value). The voltage value used is the phase to phase voltage.
That means that the voltage and the current are in phase.
The current is the same in the three live wires. The voltage can be described as the line voltage (phase to neutral) or the phase voltage (phase to phase) which is larger by a factor of sqrt(3). So a line voltage of 230 v corresponds to a phase voltage of 400 v.