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That would have to be when the dipole axis is perpendicular to the field.
The work done by you to turn the electric dipole end for end in a uniform electric field depends on the initial orientation of the dipole with respect to the field. If the dipole is initially oriented such that its positive and negative charges are parallel to the electric field, then no net work is done as the electric field does not do any work on the dipole as the electric field lines do not transfer any energy. On the other hand, if the dipole is initially oriented such that its positive and negative charges are perpendicular to the electric field, then work is done by you to turn the dipole as the electric field exerts a force on the charges in the dipole in opposite directions, causing them to move in opposite directions. As a result, you have to do work to move the charges and turn the dipole.
expression for the electric field in the perpendicular bisector plane of a dipole
when dipole moment,torque and electric field all the three are perpendicular to each other.
when angle 0 b/w dipole moment vector p and electric field vector E is zero then potential energy of dipole, U=-pEcos0 =-pE and torque=pEsin0=0;which means that the electric dipole is in stable equilibrium.
Zero Dipole would set itself such that dipole moment vector is along the electric field vector
That would have to be when the dipole axis is perpendicular to the field.
yes, there is a NET field .electric dipole experiences a net field .(not in uniform E.Field)
The work done by you to turn the electric dipole end for end in a uniform electric field depends on the initial orientation of the dipole with respect to the field. If the dipole is initially oriented such that its positive and negative charges are parallel to the electric field, then no net work is done as the electric field does not do any work on the dipole as the electric field lines do not transfer any energy. On the other hand, if the dipole is initially oriented such that its positive and negative charges are perpendicular to the electric field, then work is done by you to turn the dipole as the electric field exerts a force on the charges in the dipole in opposite directions, causing them to move in opposite directions. As a result, you have to do work to move the charges and turn the dipole.
expression for the electric field in the perpendicular bisector plane of a dipole
So interesting query! As we keep the dipole with its dipole moment along the direction of the electric field then it will be in stable equilibrium. IF we keep the same dipole inverted ie its dipole moment opposite to the external field then the dipole will be in unstable equilibrium.
when dipole moment,torque and electric field all the three are perpendicular to each other.
uses of dipole materials
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
when angle 0 b/w dipole moment vector p and electric field vector E is zero then potential energy of dipole, U=-pEcos0 =-pE and torque=pEsin0=0;which means that the electric dipole is in stable equilibrium.
direction-along the axis of dipole from -q to +q.
in magnetic relays