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A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The number of atoms is 1,50553521.10e23.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
This depends on the mass of the gold sample.
We have now way of knowing unless we know the initial number of C-14
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
The number of atoms is 1,50553521.10e23.
Approx. 9.1024 atoms.
1,600
The answer is 6,2729.10e+26 carbon atoms.
Take the actual sample weight of 13grams, and divide it by the atomic weight of chromium. This gives you your molar percentage of atoms. Now multiply this molar percentage by Avogadro's constant, the number of atoms in one mole, and this will give you your number of atoms in the sample.
9 half lives have elapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N-14.
The number of potassium atoms is 2,04.10e21.
Only 75 atoms
This depends on the mass of the gold sample.
This depends on the mass of the gold sample.
150 (50 x 3)