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The first 1C-OH is chemically originating1) from an aldehyd (which is reducing)

the fourth (and all other) 4C-OH are from alkanolic origin (non-reducing).

1) 'Pyranose ring closure' of -1C=O with -5C-OH to hemi-acetal formation of

-1C(OH)-O-5C- is a easily reversible reaction.

It's not the (OH) but the -O- which makes it reducing.

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Q: Why is the first carbon in glucose a reducing while the fourth carbon is not?
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