If you are referring to the voltage after the rectifiers in a powersupply, it is due to the voltage drop across the rectifiers.
why will Vpk not be exactely equal to the peak voltage of the altenating supply
In a series circuit the current flow in each element is equal but voltage across the each element is differ. In a parallel circuit the voltage across the each element is equal but current flow in each element is differ.
1 litre of water is exactly 1 Kilogram. -Other materials may differ.
Power, in 'watts'.
They are not equal; they differ by 0.072.
Series resonance isn't generally referred to as 'voltage resonance', but the expression probably comes from the fact that, at resonance, the voltage drop across the inductive component of a circuit is exactly equal to the voltage drop across the capacitive component of the circuit and, if the resistance of the resonant circuit is low in comparison with its reactance, then each of these voltage drops can be significantly higher than the supply voltage.
Well, not exactly. "I'm sorry" is exactly equal to "I apologize."
the source voltage is the voltage that measured exactly after the voltage source , but the terminal voltage is the voltage that measured in the load terminals , which equal to the source voltage minus the drop voltage on the transmission line .
The voltage is greater than the applied voltage, why?
They differ by thickness of the aluminum and weight.
It is equal to exactly 110.
No. Voltage divided by resistance is equal to current.