In a SN1 reaction, the nucleophile (in this case, nitrate ion) attacks the carbon atom that is bonded to the leaving group. Since the carbon atom is already bonded to the leaving group, it is not as electronegative as it would be if it were bonded to a hydrogen atom. This makes the carbon atom a less effective nucleophile. In addition, the nitrate ion is a weaker nucleophile than other nucleophiles, such as halide ions, because it is not as electronegative.
This is a really great question that I often drill into my students heads. During the attack of an alkyl halide by a nucleophile, we see the electrons from the Nucleophile emptying into the anti-bonding orbital present at the rear of the carbon atom. It is at this position..... backside.....that the large-lobed anti-bonding orbital is located. This is seen in the SN2 process. In an SN1 process, a carbocation can form,,,,, resulting in an sp2 intermediate....which can readily be attacked by a nucleophile. Halogens such as I- are excellent leaving groups since the anion is stable. F- is a poor leaving group, since the huge negative charge is so concentrated that is results in an unstablized anion.
alcoholic medium is necessary because if it is aqueous then CN- will hydrolysis water to form HCN and OH-.Therefore there will be two nucleophile in aqueous CN- AND OH-.
Alkenes have pi bonds that are readily available to react because the strength of a pi bond isn't as strong as a sigma bond. Pi electrons will attack the nucleophile to form the respective carbocation. Alkanes only contain sigma bonds and have no pi electrons to attack a nucleophile. In order for an alkane to become a strong enough nucleophile it must not be sterically hindered (primary carbons prefered to tertiary) and most likely deprotenated by a very strong base ( likely stronger than sodium amide ).
Metal and water are both excellent conductors of electricity.
H20 is a nucleophile it has a free lone pair of electrons which is a main feature of nucleophile, however, it is a weak nucleophile
Indicator will changes the colour according to H+ ion present in a solution. Reagent : consist of electrophile and nucleophile. It help in the attachment of nucleophile to the electrophile and electrophile to the nucleophile. Mirza
A reaction with alkyl halides in NaI with acetone is by the Sn2 mechanism. The rate for an Sn2 mechanism is directly proportional to the concentration of the nucleophile: rate = k[nucleophile][alkylhalide] If the iodine solution (the nucleophile) is half as concentrated, then the rate will also be halved. rate = k [nucleophile]/2 [alkyl halide]
Yes it is a nuclephile.It has a lone pair
No it is not electrophilic.It is a nucleophile
In a SN1 reaction, the nucleophile (in this case, nitrate ion) attacks the carbon atom that is bonded to the leaving group. Since the carbon atom is already bonded to the leaving group, it is not as electronegative as it would be if it were bonded to a hydrogen atom. This makes the carbon atom a less effective nucleophile. In addition, the nitrate ion is a weaker nucleophile than other nucleophiles, such as halide ions, because it is not as electronegative.
This is a really great question that I often drill into my students heads. During the attack of an alkyl halide by a nucleophile, we see the electrons from the Nucleophile emptying into the anti-bonding orbital present at the rear of the carbon atom. It is at this position..... backside.....that the large-lobed anti-bonding orbital is located. This is seen in the SN2 process. In an SN1 process, a carbocation can form,,,,, resulting in an sp2 intermediate....which can readily be attacked by a nucleophile. Halogens such as I- are excellent leaving groups since the anion is stable. F- is a poor leaving group, since the huge negative charge is so concentrated that is results in an unstablized anion.
My guess is, that any available water can act as a nucleophile and displace the halide producing the alcohol.
Ch3CN
Nu attacks carbon, Ba abstracts H2
This is thought to be because NCl3 hydrolysis is initiated by a water molecule, acting as a nucleophile, attacking a chlorine. The N - Cl bond is only very slightly polar, with the chlorine as the slightly positive end. The N - F bond on the other hand is much more polar, and in the opposite direction (fluorine is highly electronegative) so there is no site for the nucleophile to attack.
alcoholic medium is necessary because if it is aqueous then CN- will hydrolysis water to form HCN and OH-.Therefore there will be two nucleophile in aqueous CN- AND OH-.