If you choose a different reference point, the numbers for torque will be different. Calculations will still work out, though - but a reference point must be chosen, and used consistently.
nope...itz not necessary that the frame should be inertial....the only necesarry condition is that the TOTAL EXTERNAL TORQUE acting ABOUT THE REFERENCE AXIS should be ZERO...
There are various physical situations in which the cross product naturally arises, for example in various relationships between electricity and magnetism. Another example is torque (the rotational equivalent of "force"): torque depends on the distance from the reference point and on the force. It also depends on the angle between the two (including the direction in the "distance"). Finally, the torque can conveniently be defined as having a "direction" that points in the axis of the resulting rotation (or angular acceleration). This gives you all the characteristics of a cross product.
hat is meant by Reluctance Torque
torque tends to rotate an object.
My car has lots of torque in first gear.
nope...itz not necessary that the frame should be inertial....the only necesarry condition is that the TOTAL EXTERNAL TORQUE acting ABOUT THE REFERENCE AXIS should be ZERO...
so that when damping torque=controlling torque,the pointer comes back to the zero position...i.e. the main role of controlling torque is to ensure to bring the pointer to the 0 position when deflecting torque is removed
Breakaway torque is the torque required to start the initial movement, in the loosening direction, of a bolt, screw, or nut from its (non−loaded) at rest position with the locking element engaged. Tightening torque is the torque necessary to move the bolt, screw, or nut along its threaded length in the tightening direction.
That would depend on the year and particular model 350, which you fail to mention. So I cannot answer your question.
It's not necessary
Not usually. If necessary it says in manual.
Firstly could you be so kind to explain to me what "linear torque" is. I'm pretty confident that torque = force x radius at which that force is applied, thus the term linear torque cannot exist. Also torque is simply the angular version of force, I'm going to take a stab at this and assume that what you really want to know is how to convert torque to force. Since the equation defining torque is T=FR, where T is torque, F is force and R is the radius at which that force is applied, then the force (by simple algebraic rearranging) is simply T/R.
If you're referring to the spindle nut for the center hub it is 118 ft lbs of torque. I replaced my wheel bearing and the paperwork with the new had a torque reference guide with it (very useful). It recommended 118 ft lbs.
That would depend on the year and particular model 350, which you fail to mention. So I cannot answer your question.
Yes it will fit. bellhousing will fit but the torque converter will not bolt up to flex plate (flywheel) not to mention the trans cant handle the increased amount of torque with big block
A couple is a mechanical term defined as a system of forces that produces a resultant moment but not a resultant force. The moment caused by a couple is different than the moment caused by a single force. The moment of a force is dependent upon a reference point (i.e. if this reference point changes the moment also changes), therefore it is a fixed (or bound) vector. However, the moment (or torque) of a couple is independent of a reference point. In other words any reference point will give the same torque. This fact is proven in Varignon's Second Moment Thereom. Since the moment (or torque) of a couple is independent of a reference point, it may be represented as a free vector. This means that the vector may be freely moved in space.
Yes. If you are going to remove the transmission to rebuild it, you may as well go ahead and replace the torque converter.. not to mention all the seals anywhere near that area.