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Input energy = output energy + losses
Therma losses are heat losses, or losses of heat energy. Just one example is the idea of thermal loss through windows in a structure. Walls can be insulated, but heat energy can pass readily through ordinary window glass. On a cold day, there are a lot of thermal losses from a structure through regular glass windows.
In a conventional fossil fuel plant, most of the lost heat goes literally up the chimney. Since nuclear facilities, most of the heat is dumped into the environment by using heat exchangers that put the heat into large bodies of water or rivers. There are other points of loss, but since about 60% to 65% of the power generated in power stations is lost in one of these two ways, the other losses are negligible.
If energy is transformed from one form to another, for example electric power to mechanical power in an electric motor, in an ideal situation there would be no losses and therefore an exact equivalent in the new form of energy. In practice there are always losses, the process is not 100 percent efficient. In the above case there will be some thermal losses due to heating in the motor windings, and some windage losses due to air resistance to the moving parts, and some frictional losses in the motor bearings. In this case the losses should not be large. In a power plant operating the Rankine cycle converting thermal energy to electric energy (see link below) large losses are inevitable, and even in the most efficient power stations more energy is lost to the cooling plant (water or air cooling) than is turned into useful output energy.
I am so sorry for your core losses
Copper losses are energy losses from the windings, due to the currents passing through them. During an open-circuit test, there is no secondary current (so no secondary copper losses) and the primary current is very low (so the primary copper losses are minimum).
Because a short-circuit test is done at very low voltage to check the transformer windings on their maximum current. The low voltage ensures that the magnetic flux in the transformer's iron core is very low so that the eddy-current losses, usually known as iron losses, are negligible.
During open circuit test on transformer, no load is connected across the secondary side. Hence, the total power drawn by the transformer is only to induce the voltage across the secondary, i.e., core loss AND negligible amount of primary copper loss. As the primary copper losses during open circuit are negligible, it is practice to attribute the open circuit power to core loss.
Since this is an open circuit test, there is no load attached, thus all losses must be internal to the transformer.
The transformer can be tested on open and short circuit to find the iron losses and copper losses separately, which uses a fraction of the power than having to run the transformer on full-load.
There are losses in d.c. transmission lines, due to their resistance. But there are no reactive losses. So, d.c. transmission lines have less losses in comparison to an equivalent a.c. transmission line.
In an open circuit test full load current does not flow, hence you wont get copper loss.
Open Circuit test is done to find out core losses of the transformers.which include Eddy Current Losses and Hysteresis Losses only, if during open circuit test secondary will have some load then I2R losses due to load current in secondary as well primary will be included in test results which is not desired while performing Open circuit test.
wires that have got good conductivity and less losses
In a short-circuit test the normal load current is passed through the transformer with minimal voltage applied. This means that the magnetic flux density in the core is also minimal, so that the only losses are the resistive losses of the transformer windings.
How technical of an answer do you want? The resistance of any fuse in any circuit should be negligible. If it is not, the circuit or the fuse is poorly designed. Of course there is resistance in the fuse which actually does matter, or else it would be able to handle an infinite amount of current without blowing from excess heat (I^2R losses). In circuits where very small resistances matter, there are other ways to deal with over current issues.