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because of conjugation with the aromatic ring

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Q: Why ortho sulphanilic acid is more stable then meta?
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Salicylic acid is ortho para directing group or meta directing group?

salicytic acid is a ortho para directing group ....however check up on that ...i am not completely certain .. Actually, it is a meta-directing group, because of the carboxylic acid functional that the salicylic acid contains. Hope that was helpful.


What are the names and formulas for the oxyacids and iodine?

Oxyacids of iodine are:- iodic acid: HIO3- iodous acid: HIO2- hypoiodous acid: HIO- ortho periodic acid: HIO4- meta periodic acid: H5IO6


Activating and deactivating group of Ortho para and meta director groups Explain?

You can either deactivate or activate the group of Ortho para and Meta director groups depending with your preference.


What is ortho meta and para in benzene?

ortho-para in benzene is meaningless these positions are for monosubstituted benzene. Meta is positions 3 and 5. Ortho is position 2 and 6 with relation to already attached group, para is 4 (opposite) to attached group.


Compare the basicity of isomers of toluidine?

As expected from Inductive(/hypercojugative) as well as ortho effect the basicity order should be: ortho-toluidine>para-toluidine>meta-toluidine. But, experimental order is: para-toluidine(Pka=5.12)>meta-toluidine(Pka=4.69)>ortho-toluidine(Pka=4.39).The order of basicity is explained by two opposing effects :i) inductive effect ii) Stability of the conjugate base. Here 2nd factor is more significant for ortho-toluidine & 1st factor is important for para-toluidine. For ortho-toluidine the conjugate base [o-MeC6H4NH3+] is destabilized by steric interaction between -NH3+ & -Me(at ortho). This desatabilization is absent with para-toluidine & meta-toluidine.Tha's why basicity of: ortho-toluidine(Pka=4.39)

Related questions

Salicylic acid is ortho para directing group or meta directing group?

salicytic acid is a ortho para directing group ....however check up on that ...i am not completely certain .. Actually, it is a meta-directing group, because of the carboxylic acid functional that the salicylic acid contains. Hope that was helpful.


What are the names and formulas for the oxyacids and iodine?

Oxyacids of iodine are:- iodic acid: HIO3- iodous acid: HIO2- hypoiodous acid: HIO- ortho periodic acid: HIO4- meta periodic acid: H5IO6


Activating and deactivating group of Ortho para and meta director groups Explain?

You can either deactivate or activate the group of Ortho para and Meta director groups depending with your preference.


What is ortho meta and para in benzene?

ortho-para in benzene is meaningless these positions are for monosubstituted benzene. Meta is positions 3 and 5. Ortho is position 2 and 6 with relation to already attached group, para is 4 (opposite) to attached group.


Sodium carbon oxygen?

Sodium (Meta)Carbonate = Na2CO3Sodium Ortho-Carbonate = Na4CO4


Why ortho benzoic acid is more acidic than para osomer?

Nitro group (-NO2), having -I and -R effect, is an electron withdrawing and deactivating group. Due to both these effects, it decreases electron density around the -COOH group of substituted(ortho, meta & para) benzoic acids and releases H+ ions, making these acidic. The nitrobenzoic acid which releases H+ group more easily is the most acidic. Due to ortho effect, ortho acids are more acidic than all other substituted acids(even if an electron donating group is present at the ortho position. The only exception is -NH2 group, in which ortho- aminobenzoic acid is NOT the strongest acid). Regarding acidity of meta and para acids, consider I and R effects. Inductive effects of meta and para acids reduce electron density around -COOH group, whereas resonance does not occur at meta position. It only occurs at para position, making the nitro group at para position a more strong withdrawer of electrons. Thus para-nitro benzoic acid is more acidic than meta-nitro benzoic acid. In short, the higher acidity of p-nitrobenzoic acid compared to m-nitrobenzoic acid is attributed to its -I and -R effect.


Compare the basicity of isomers of toluidine?

As expected from Inductive(/hypercojugative) as well as ortho effect the basicity order should be: ortho-toluidine>para-toluidine>meta-toluidine. But, experimental order is: para-toluidine(Pka=5.12)>meta-toluidine(Pka=4.69)>ortho-toluidine(Pka=4.39).The order of basicity is explained by two opposing effects :i) inductive effect ii) Stability of the conjugate base. Here 2nd factor is more significant for ortho-toluidine & 1st factor is important for para-toluidine. For ortho-toluidine the conjugate base [o-MeC6H4NH3+] is destabilized by steric interaction between -NH3+ & -Me(at ortho). This desatabilization is absent with para-toluidine & meta-toluidine.Tha's why basicity of: ortho-toluidine(Pka=4.39)


What do you mean by the donor and acceptor ions?

Donor group are ortho-para directory groups that means increases in pai density of ortho para directory. Adaptor group meta directing groups that means increases in pai density of meta directing groups.


What are the examples of Ortho and para directing group and mata directing group?

Electrophilic Aromatic Substitution is an example of Ortho and para directing group and meta directing group.


What are the differences between ortho hydrogen and para hydrogen?

Positioning around a benzene ring relative to the major functional group. Para is opposite, ortho is next to, meta is in between.


Why does para direction occur in preference to ortho?

There are 3 possible places for the nitro group to attach: An ortho, meta, or para position. To understand the stability of the carbocation, we need to look at the resonance structures for a given attack and see what the results are. The first resonance structure of the ortho attack results in a positive charge on the carbon with the hydroxyl group. This happens to be the most stable of the 3 resonance structures for an ortho attack because the two negative electron pairs in the oxygen act to stabilize the positive charge on the carbon. The other two resonance forms leave a carbon with a hydrogen attached, to hold the positive charge. Hydrogen can do nothing to stabilize the charge and thus, these are less stable forms. In the para attack situation, notice that the second resonance form also puts a positive charge on the carbon with the hydroxyl group. This provides for stability just as it does in the case of an ortho attack and thus, the middle resonance form is very stable. Finally, in the meta attack situation, all of the resonance forms result in a positive charge on a carbon with only a hydrogen attached. None of these is stable, and thus, meta attack with a hydroxyl group attached, is a very small percentage of the product. So the electron pairs in the oxygen act to stabilize the ortho and para attacks.


What are the prefixes used to designate substituent positions on disubstituted benzene compounds?

ortho- (1,2), meta- (1,3), para- (1,4)