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Klonopin is a drug derived from Clonazepam, an anti-convulsant that is used to prevent seizures, such as epilepsy. The molecular weight is 315.7112. The molecular formula is C15H10ClN3O3.
The softness of alkali metals has to do with metallic bonding in terms of bonding and anti bonding orbitals. In molecular orbitals, there are the s, p, d orbitals with corresponding anti-bonding orbitals. For alkali metals, the s orbital is only partially filled. This means that the bonds between each atom are weak because only a cloud of s-orbital electrons are holding them together. As we move right across the periodic table the strength of metals reach a maximum at about group 7-8. This is because at this point anti-bonding and bonding orbitals are both partially filled and this maximizes the amount of unpaired electrons that participate in the electron cloud that holds metallic bonds together. As we proceed further right (toward Au) the bonds become weaker because the bonding and anti-bonding orbitals begin to fill and pair up. This means these electrons do not participate in the electron cloud of metallic bonding. Thus a weaker bond (softer metal) is formed.
I wanted explain it using an MO diagram but it's a little difficult to write in this format. I'll just go through with how to construct it and the results. Firstly, note that the atomic orbitals of the Oxygen elements are of the same energy levels so we can draw them parallel with respect to the diagram: OrbitalsO O We can then draw in the electron configuration with respect to each individual atom. It follows that: Orbitals2p _|_|_2s _1s _Orbitals2p +-|+-|_2s +-1s +- *where +/- indicates sign of coefficient of electron spin number* Now that the two atoms are interacting, the probability regions defined by Schrodinger's wave equation are altered and new "molecular" solutions/orbitals are defined. Because of the nature and behavior of waves, and by application of the photoelectric effect, different interactions lead to different consequences. If a wave is in phase with another wave they result in an increased amplitude: this gives electrons the most ideal energy position and may result in a decrease of energy over atomic configurations.However, it also means that there will be times of destructive interference as opposed waves collide. This collision leads to nodes of complete interference and oppose the bonding of the elements. Such regions are known as anti-bonding orbitals. Now we can draw in our molecular orbitals and fill them according to the aufbau principle, where electrons will fill according to the lowest possible energy state. Also note that the 2pσ bond in Oxygen is the lowest in energy as it is larger than nitrogen.Anti-Bonding Orbitals denoted by * 2P :-2pσ* 2pπ* 2pπ 2pσ2S :- 2sσ* 2sσ1S : -1sσ* 1sσFrom 1sσ, the energy increases in each molecular orbital. Using both Oxygen atom's electrons we fill the orbitals. The diagram will have these results:2P :-2pσ* 2pπ* + +2pπ +- +-2pσ + -2S :- 2sσ* +-2sσ +-1S : -1sσ* +-1sσ + -The idea is that the electrons left 2 half filled degenerate orbitals. This makes Oxygen a diradical. If we now calculate the bond order to see which state the elements favor. Bond order is the half the difference of bonding electrons to anti-bonding electrons. Here we have (10 bonding - 6 anti-bonding)/2. 4/2 = 2. Therefore:By molecular orbital Theory, the gas O2 is energetically favored to the elemental Oxygen and is of Bond order 2. It will have a double bond.
Anti- Matter
Standard PY and PZ cannot form bonding and anti bonding molecular oribitals due to their structural differences. Depending on the composition of the bonds, most atoms and molecules can create orbitals.
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Electrons in a bonding orbital have lower energy levels than the average energy of a valence electrons in the isolated atoms between which the orbital is formed. Antibonding orbitals do not meet this criterion, so that anitbonding orbitals can be stable only in conjunction with bonding orbitals, whereas bonding orbitals can be formed without any accompanying antibonding orbitals.The molecular orbitals which is formed by the addition of atomic orbitals is called bonding molecular orbitals.The molecular orbitals which is formed by the subtraction of atomic orbitals is called antibonding molecular orbitals.
With itself. Molecular bonding theory and the bond order show a sigma pi discrepancy ( bonding/anti-bonding ) that disallows this tetra-covalent carbon to carbon interaction. Google this for a fuller explanation.
Because that's the way physics works. There really isn't a "why". It's kind of like asking why there are negative numbers. There just are.
Molecular Orbital Theory (MOT):•Basic idea of MOT is that atomic orbitals of individual atoms combine toform molecular orbitals. Electrons in molecule are present in themolecular orbitals which are associated with several nuclei.•The molecular orbital formed by the addition of atomic orbitals is calledthe bonding molecular orbital (s ).•The molecular orbital formed by the subtraction of atomic orbital is calledanti-bonding molecular orbital (s*).•The sigma (s ) molecular orbitals are symmetrical around the bond-axiswhile pi (p ) molecular orbitals are not symmetrical.•Sequence of energy levels of molecular orbitals changes for diatomicmolecules like Li2, Be2, B2, C2, N2 is 1s < *1s < 2s< *2s < ( 2px = 2py)
Bonding molecular orbital Its energy is less than that of parent atomic orbital.It is more stable than the parent atomic orbital.In B.M.O, the probability of finding electrons is maximum.Contribution of B.M.O is maximum towards the shape of molecule.Anti-bondingmolecular orbital Its energy is greater than that of parent atomic orbital.It is less stable than the parent atomic orbital.In A.B.M.O, the probability of finding electrons is minimum.It does not contribute towards the shape of molecule.
HI has a bond order of 1. H 1s1 + I 5p5 gives one filled (2 electrons) sigma bonding oribital and one empty anti-bonding orbital. bond order= 1/2 (bonding electrons-anti-bonding electrons) = 1/2(2-0) = 1
there are two
Oxygen, O2 is paramagnetic indicating 2 unpaired electrons, howver simple bonding schemes for O2 with its 12 electrons would predict that they would all be paired. A molecular orbital treatment of O2 shows that there are two degenerate (equal energy) anti-bonding pi orbitals that each holds one electron.
Klonopin is a drug derived from Clonazepam, an anti-convulsant that is used to prevent seizures, such as epilepsy. The molecular weight is 315.7112. The molecular formula is C15H10ClN3O3.
If you are going by the electron configuration of nitrogen then the unpaired electrons in the 2p shell would indicate that it is paramagnetic. However experiments show that it is diamagnetic. You must remember that nitrogen is a diatomic element and as such is found as N2. The molecular orbital theory explains how there are no unpaired electrons in the bonds between the two N atoms. The 1s and 2s molecular orbitals are completely filled and all of the bonding 2p orbitals are also filled. There are no electrons in the any of the 2p anti-bonding orbitals. Seeing a molecular orbital diagram for N2 will clarify what i mean.